Graph the line with slope −3/4 passing through the point , (3,3)

1 answer:

Nookie1986 [14]4 years ago

8 0

Y = mx + b
slope(m) = -3/4
(3,3)....x = 3 and y = 3
now we sub and find b, the y int
3 = -3/4(3) + b
3 = -9/4 + b
3 + 9/4 = b
12/4 + 9/4 = b
21/4 = b.....or 5.25 for graphing purposes

so ur equation is : y = -3/4x + 21/4

ur y int = (0,21/4) or (0,5.25)

ur x int can be found by subbing in 0 for y and solving for x
y = -3/4x + 21/4
0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
x = 84/12 = 7.....so ur x int is (7,0)

so plot ur points (7,0) and (0,5.25)....now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)

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Answer:

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Step-by-step explanation:

Let suppose that Han's younger sister accelerates at constant rate, then, acceleration ( $a$ ), measured in meters per square second, can be calculated by the following equation:

$a = \frac{v_{f}-v_{o}}{t_{f}-t_{o}}$

Where:

$t_{o}$ , $t_{f}$ - Initial and final times, measured in seconds.

$v_{o}$ , $v_{f}$ - Initial and final speeds, measured in meters per second.

If we know that $t_{o} = 3\,s$ , $t_{f} = 5\,s$ , $v_{o} = 0.5\,\frac{m}{s}$ and $v_{f} = 1.5\,\frac{m}{s}$ , the acceleration of the younger sister is: