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2 years ago

Help anyone please.................................

Mathematics

1 answer:

Helen [10]2 years ago

5 0

Answer:

- 3y

Step-by-step explanation:

$-\sqrt{9y^{2} } =-(9)^{\frac{1}{2} } (y)^{\frac{2}{2} } =-\sqrt{9} (y)^{1} =-3y$

Hope this helps

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Alla [95]

Let the measure of side AB be x, then, the measue of side AE is given by

$AE=\sqrt{9^2-x^2}$ .

Now, ABCD is a square of size x, thus the area of square ABCD is given by

$Area=x^2$

Also, AEFG is a square of size $\sqrt{9^2-x^2}$ , thus, the area of square AEFG is given by

$Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2$

The sum of the areas of the two squares ABCD and AEFG is given by

$x^2+81-x^2=81$

Therefore, the number of square units in the sum of the areas of the two squares ABCD and AEFG is 81 square units.

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3 years ago

-7 < 3x + 2 < 5. Solve for x

yarga [219]

Answer:

-3 < x < 1, This is the domain

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2 years ago

Solve the equation. StartFraction dy Over dx EndFraction equals5 x Superscript 4 Baseline (1 plus y squared )Superscript three h

dangina [55]

Answer:

Step-by-step explanation:

To solve the differential equation

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Now, integrate both sides

To integrate dy/(1 + y²)^(3/2), use the substitution y = tan(u)

dy = (1/cos²u)du

So,

dy/(1 + y²)^(3/2) = [(1/cos²u)/(1 + tan²u)^(3/2)]du

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Because cos²u + sin²u = 1 (Trigonometric identity),

The equation becomes

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Integral of cosu = sinu

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We then have

cos(arctany) = y/√(1 + y²)

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dy/(1 + y²)^(3/2) = 5x^4 dx

y/√(1 + y²) = x^5 + C

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3 years ago

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vampirchik [111]

Answer:

R = (3P-30)/8

Step-by-step explanation:

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multiply each side by $\frac{3}{8}$ to get:

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3 years ago

How to do percentages ?

Rus_ich [418]

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3 years ago

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