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The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²

a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 

Therefore, the pool can hold 65.84 ft³ of water
Answer:
g=56
Step-by-step explanation:
In similar shapes, corresponding sides are always in the same ratio.
For example,
if the sides in triangle 1 were a and b, and triangle 2 had side lengths c and d, c and a had the same ratios, and b and d had the same ratios
and triangle 1 was similar to triangle 2, the ratio between the sides of the triangles would be
a/c, which is also equal to b/d
What that means is that in this situation, 8/5=g/35.
8/5=g/35
Cross multiply.
(8)*(35)=g*(5)
280=5g
g=56
Answer:
<u>Total number of strikeouts:</u>
<u>Total number of at bats:</u>
<u>Hits = times - strikeouts:</u>
<u>Percentage:</u>