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4 years ago

What is the smallest lithostratigraphic rock unit?

Physics

2 answers:

svlad2 [7]4 years ago

8 0

Answer:

what happened when thanos snapped his fingers

actual answer:

bed

formation bed layer group

goldenfox [79]4 years ago

6 0

Answer:

dust

Explanation:

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To meet a U.S. Postal Service requirement, employees' footwear must have a coefficient of static friction of 0.5 or more on a sp

liq [111]

Answer:

Minimum time interval (t2)=0.90 SECONDS

Explanation:

coefficient of friction for employees footwear = 0.5

coefficient of friction for typical athletic shoe = 0.810

frictional force = coefficient of friction X acceleration due to gravity X mass of body
Acceleration due to gravity is a constant = 9.81 m/s
Let frictional force for employee footwear = FF1
Let frictional force for athletic footwear =FF2

FF1 = O.5 X 9.81 X mass of body

= 4.905 x mass of body

FF2 = 0.810 X 9.81 X mass of body

= 7.9461 x mass of body

The body started from rest there by making the initial velocity zero ( u = 0)

From d= ut + 1/2 a x $t^{2}$

d = $\frac{1}{2}$ x a x $t^{2}$ .....................................i

where d= distance and it is given as 3.25m

F =ma ...................................ii

making acceleration subject of the formula from equation ii

a = $\frac{F}{m}$

Making t subject of formula from equation (i)

t= $\sqrt{\frac{2d}{(f/m} }$

where

$\frac{FF1}{Mass of body}$ = 4.905
$\frac{FF2}{Mass of body}$ =7.9461

Let

t1 = minimum time taken for frictional force for employee foot wear

t1 = $\sqrt{\frac{6.5}{4.905} }$ =1.15 seconds

t2 = $\sqrt{\frac{6.5}{7.9461} }$ = 0.90 seconds

THANK YOU

5 0

3 years ago

Richard is driving home to visit his parents. 135 mi of the trip are on the interstate highway where the speed limit is 65 mph .

Elis [28]

<h2>Answer:</h2>

He saves 13.2 minutes

<h2>Explanation:</h2>

Hey! The question is incomplete, but it can be found on the internet. The question is:

How many minutes did he save?

Let's call:

$t_{1}:Time \ at \ speed \ 65mph \\ \\ t_{2}:Time \ at \ speed \ 73mph \\ \\ v_{1}=65mph \\ \\ v_{2}=73mph$

We know that the 135 miles are on the interstate highway where the speed limit is 65 mph. From this, we can calculate the time it takes to drive on this highway. Assuming Richard maintains constant the speed:

$v=\frac{d}{t} \\ \\ d:distance \\ \\ t:time \\ \\ v:velocity \\ \\ t_{1}=\frac{d}{v_{1}} \\ \\ t=\frac{135}{65} \\ \\ t_{1}=2.07 \ hours$

Today he is running late and decides to take his chances by driving at 73 mph, so the new time it takes to take the trip is:

$t_{2}=\frac{135}{73} \\ \\ t_{2}=1.85 \ hours$

So he saves the time $t_{s}$ :

$t_{s}=t_{1}-t_{2}=2.07-1.85=0.22 \ hours$

In minutes:

$t_{s}=0.22h\left(\frac{60min}{1h}\right) \\ \\ \boxed{t_{s}=13.2min}$

5 0

3 years ago

Last edit was 3 minutes ago

SCORPION-xisa [38]

Answer:chemical change. a change that produces matter with a different composition than the original matter. chemical property. the ability of a substance to undergo a specific chemical change. chemical reaction

Explanation:

A “chemical change” is a change that produces matter with a different composition than the original matter.

3 0

3 years ago

with what force will Annabella’s car hit a tree if her car has a mass of 5000 kg and an acceleration of 2 m/s2

Svet_ta [14]

Answer:

F=10,000N

Explanation:

F=ma

m=5000kg

a=2m/s^2

$F=(5000kg)*(2m/s^{2} )\\\\\\\\F=10000N$

4 0

3 years ago

Read 2 more answers

What is the acceleration of a 1.5 kg brick that is thrown with a force of 200 N?

Fynjy0 [20]

Answer:

133.33 m/s2

Explanation:

Acording to Newton's 2nd law of motion

f=ma

a=f/m

a=200/1.5

a=133.33 m/s2

3 0

3 years ago