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3 years ago

A dart with a mass of 0.5kg is thrown at 15m/s and sticks into a 1kg apple hanging

Physics

1 answer:

zimovet [89]3 years ago

6 0

Answer:

Before the collision:

m v1 = .5 kg * 15 m/s = 7.5 kg-m/s

Incidentally, after the collision

(M + m) v2 = 7.5

v2 = 7.5 / (1 + .5) = 5 m/s

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Answer:

9.2 N, with significant figure rounding (2 s.f.)

Explanation:

This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:

Note that where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.

Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg.

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The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.

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The time it takes for the egg to stop is 0.072 seconds.

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We only care about the magnitude, not direction. The answer is 9.2 N.

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2 years ago

What is in between the nucleus and the electrons in an atom?

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Answer:

D. Empty Space

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2 years ago

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Answer:

$\theta = n\pi/2, {\rm where~n~is~an~integer.}$

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Similarly,

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$\vec{A}.\vec{B} = |\vec{A}|.|\vec{B}|.\cos(\theta)$

So,

$\vec{v}(t).\vec{a}(t) = |\vec{v}(t)|.|\vec{a}(t)|.\cos(\theta)\\36t = \sqrt{4 + 7 + 36t^2}.6.\cos(\theta)$

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3 years ago

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