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2 years ago

A dart with a mass of 0.5kg is thrown at 15m/s and sticks into a 1kg apple hanging

Physics

1 answer:

zimovet [89]2 years ago

6 0

Answer:

Before the collision:

m v1 = .5 kg * 15 m/s = 7.5 kg-m/s

Incidentally, after the collision

(M + m) v2 = 7.5

v2 = 7.5 / (1 + .5) = 5 m/s

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Given the resistivities below, which material is best described as an insulator?

koban [17]

Answer: D) 3.2 × 10^8

Explanation: Insulators are best described as materials which are poor conductors of electricity and hence do not allow passage of electricity through them. Resistivity are hence used to describe property or characteristic of a material which does not allow the flow or passage of electric current.

In summary, materials which high resistivity values are referred to as Insulators. Conversely, those with low resistivity or high conductivity values are called conductors while those with intermediate values are named semiconductors.

In the question given above, the material with a resistivity value of 3.2 × 10^8 - - - has a very high resistivity value (320000000Ω), the other options given have very low resistivity values ; 0.0000000017, etc and are most likely to be conductors due to their excessively low resistivity values.

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3 years ago

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vladimir2022 [97]

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3 years ago

How does self efficacy relate to sports performance?

vitfil [10]

Answer: Individuals with high self efficacy will participate readily and more frequently, will put more effort in and persist longer, enhancing performance in sport and exercise

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1 year ago

A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, c

Leno4ka [110]

Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

Using conservation of momentum,

Initial thrower has a momentum of mv; $m_{total$ v

(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg + 0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

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2 years ago

Two technicians are discussing electromagnetic induction. Technician A says that the induced voltage can be increased if the spe

Inga [223]

Answer:Both

Explanation:

There are three ways to increase the induced voltage in electromagnetic induction:

1) increase the speed at which the conductor moves through the magnetic field. This means that the lines of flux are cut more quickly and more emf is induced.

2) use stronger magnets which provides a stronger magnetic field and more densely packed lines of flux.

3) use a coil of multiple loops.

Hence both technicians were correct.

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2 years ago