1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivanshal [37]
4 years ago
14

The gases inside of a normal tire are usually measured when they are at ambient standard temperature (298 K) & under a contr

olled pressure of 32.5 PSI in order for the device to remain “stable” – not blow up! Sometimes, driving conditions cause the pressure inside the tire to reach 40.68 PSI, what is the temperature of the air inside the tire at 40.68 PSI (in °C)?
Chemistry
1 answer:
Anastaziya [24]4 years ago
8 0

Answer:

100°C

Explanation:

The following were obtained from the question:

Initial temperature (T1) = 298 K

Initial pressure (P1) = 32.5 Psi

Final pressure (P2) = 40.68 Psi

Final temperature (T2) =..?

The final temperature can be obtained as follow:

P1/T1 = P2/T2

32.5/298 = 40.68/T2

Cross multiply to express in linear form

32.5 x T2 = 298 x 40.68

Divide both side by 32.5

T2 = (298 x 40.68) /32.5

T2 = 373K

Next, we shall convert 373K to celsius.

This is illustrated below:

T(°C) = T(K) – 273

T(K) = 373

T(°C) = 373 – 273

T(°C) = 100°C

Therefore, the temperature of the air inside the tire at 40.68 Psi is 100°C

You might be interested in
What forms the organic portion of soil?
telo118 [61]

Answer:

<h2>Dead & Decaying Organisms</h2>

Explanation:

There are many inorganic components of soil, such as clay. However, soil is mainly comprised of dead and decaying organisms. For example, old, and decaying plants.

<em>PLEASE MARK BRAINLIEST</em>

5 0
3 years ago
The pressure exerted by 1.5 mol of gas in a 13 L flask at 22 °C is ____ kPa
sukhopar [10]

Answer:

282.7KPa

Explanation:

Step 1:

Data obtained from the question.

Number of mole of (n) = 1.5 mole

Volume (V) = 13L

Temperature (T) = 22°C = 22 + 273°C = 295K

Pressure (P) =..?

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the pressure exerted by the gas.

This can be obtained by using the ideal gas equation as follow:

PV = nRT

P = nRT /V

P = 1.5 x 0.082 x 295 / 13

P = 2.79atm.

Step 3:

Conversion of 2.79atm to KPa.

This is illustrated below:

1 atm = 101.325KPa

Therefore, 2.79atm = 2.79 x 101.325 = 282.7KPa

Therefore, the pressure exerted by the gas in KPa is 282.7KPa

8 0
3 years ago
A solution is made by mixing 33.0 ml of ethanol, C2H6O and 67.0 ml of water. Assuming ideal behavior, what is the vapor pressure
ivann1987 [24]
Grams ethanol = 33 ml times .789 gms/ml = 26.037 gms 

<span>Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles </span>

<span>Moles water = 67 ml or 67 grams/18 gms/mole = 3.22 moles </span>

<span>total moles = .57 + 3.72 = 4.29 moles </span>

<span>Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13</span>

<span>Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87</span>

<span>Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr </span>

<span>partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr </span>

<span>Total vapor pressure over solution = 5.71 torr + 15.23 torr = 20.94 torr</span>
7 0
3 years ago
If the reaction N2 (g) + 3 H2 (g) --&gt; 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

4 0
3 years ago
In the water cycle, matter moves against the pull of gravity during
V125BC [204]
Evaporation and transpiration
5 0
4 years ago
Read 2 more answers
Other questions:
  • A chemical formula includes the symbols of the elements in the compound and subscripts that indicate
    5·1 answer
  • What is the difference between water and alcohol
    5·1 answer
  • The vapor pressure of pure water at 250C is 23.77 torr. What is the vapor pressure of water above a solution that is 1.500 m glu
    6·1 answer
  • Objects that can bew seen only under magnification
    15·1 answer
  • PLEASE HELP ASAP I'LL GIVE BRAINLIEST: What would be the correct electron dot structure for silicon?
    10·1 answer
  • A lack of diversity in a population could possibly cause (2 points)
    9·2 answers
  • If the concentration of mercury in the water of a polluted lake is 0.250 μg (micrograms) per liter of water, what is the total m
    5·1 answer
  • What is the degree of oxidation of a simple substance​
    11·2 answers
  • The table above this place up icicle properties of a diamond by the property names have been left out of the top row which prope
    13·1 answer
  • What evidence supports a conservation law? 6 CO2 → C6H12O6 6 O2 6 CO2 6 H2O light → C6H12O6 6 O2 6 H2O light → C6H12O6 6 O2 6 CO
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!