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miv72 [106K]
3 years ago
9

Help please?

Chemistry
2 answers:
Nadusha1986 [10]3 years ago
7 0
If I am correct only 1
Reptile [31]3 years ago
5 0

Answer:

1.55x10⁻⁵ moles does the patien take each day

Explanation:

Let's find out the molar mass of ibuprofen, in first place.

C₁₃H₁₈O₂

C = 12 g . 13 = 156

H = 1 g . 18 = 18

O = 16 g. 2 = 32

156 + 18 + 32 = 206 g/mol

In 1 mol of ibuprofen, we have 206 grams of compound.

Mass of compound / Molar mass = Moles of compound

Now, let's convert mg to g

3.2 mg / 1000 = 3.2x10⁻³ g

3.2x10⁻³ g / 206 g/m = 1.55x10⁻⁵ moles

You can say 1.55x10⁻⁵ moles

1.55x10⁻⁵ moles . 1000 = 0.015 mmoles

1.55x10⁻⁵ moles . 1x10⁶ = 15.5 μmoles

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Boyle’s law states that the volume of a gas is inversely proportional to its pressure if the
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Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its temperature if<u> the temperature and the number of particles are constant.</u>

<h3>Further Explanation</h3><h3>Boyles’s law  </h3>
  • This gas law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
  • Therefore, when the volume of an ideal gas is increased at constant temperature then the pressure of the gas will also increase.
  • Mathematically;  Volume α 1/Pressure

                               Vα1/P

  • Therefore, constant k, is = PV
<h3>Other gas Laws</h3><h3>Gay-Lussac’s law  </h3>
  • It states that at constant volume, the pressure of an ideal gas I directly proportional to its absolute temperature.
  • Thus, an increase in pressure of an ideal gas at constant volume will result to an increase in the absolute temperature.
<h3>Charles’s law</h3>
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • Therefore, an increase in volume of an ideal gas causes a corresponding increase in its absolute temperature and vice versa while the pressure is held constant.
<h3>Dalton’s law  </h3>
  • It is also known as the Dalton’s law of partial pressure. It states that the total pressure of a mixture of gases is always equivalent to the total sum of the partial pressures of individual component gases.
  • Partial pressure refers to the pressure of an individual gas if it occupies the same volume as the mixture of gases.

Keywords: Gas law, Boyles's law, pressure, volume, absolute temperature, ideal gas

<h3>Learn more about:</h3>
  • Boyles’s law: brainly.com/question/2438000
  • Gay-Lussac’s law: brainly.com/question/2438000
  • Charles’s law:brainly.com/question/2438000
  • Dalton’s law:brainly.com/question/2438000

Level: High school

Subject: Chemistry

Topic: Gas laws

Sub-topic: Boyle's Law  

3 0
3 years ago
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Forests and prairies are examples of ecosystems on land. An ecosystem is a community of living things. Members survive by interacting with each other and with their environment. At first glance, the ocean seems like one big ecosystem.


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3 years ago
How many cm 3 are in 0.14 m 3?
nlexa [21]

Answer:

There are 14 cm in 0.14 m

5 0
3 years ago
1. Some athletes have as little as 3.0% body fat. If such a person has a body mass of 65 kg, how many pounds of body fat does th
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1. 3.0% ----> 3.0 kg fat= 100 kg body weigh
also remember that 1 kg= 2.20 lbs

65 kg  \frac{3.0 kg}{100 kg} x  \frac{2.20 lb}{1 kg} = 4.29 lbs

2. 0.94 g/mL----> 0.94 grams= 1 mL
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3 years ago
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What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
rodikova [14]

Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
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