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den301095 [7]
4 years ago
15

You are hungry and decide to go to your favorite neighborhood fast-food restaurant. You leave your apartment and take the elevat

or 10 flights down (each flight is 3.0 m) and then go 15 m south to the apartment exit. You then proceed 0.2 km east, turn north, and go 0.1 km to the entrance of the restaurant.Part ADetermine the displacement from your apartment to the restaurant. Use unit vector notation for your answer, being sure to make clear your choice of coordinates.Take the beginning of the journey as the origin, with north being the y-direction, east the x-direction, and the z-axis vertical.Part BHow far did you travel along the path you took from your apartment to the restaurant?Part CWhat is the magnitude of the displacement you calculated in part A?
Physics
1 answer:
Aneli [31]4 years ago
4 0

Answer:

A. (200i + 85j - 30k)m

B.  345m

C. 219.37 m

Explanation:

UP: +VE Z

NORTH: +VE Y

EAST: +VE X

A.

DISPLACEMENT : (0.2*1000 i + (-15+0.1*1000)j + (-3*10)k) m

                            = (200i + 85j - 30k)m

B. total distance = 10*3+15+200+100 = 345m

C.

Magnitude = \sqrt{{200^{2} } +85^{2} +(-30)^{2} = 219.37 m

unit vector = \frac{200i+85j-30k}{219.4}

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A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min
Lubov Fominskaja [6]

Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

let the velocities be

v1=100km/h

v2=55km/h

v3=35km/h

a. Determine the average speed for the trip. km/h

first we have to solve for the distance

S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

b. the distance is 93.38km

6 0
4 years ago
What are the potential out comes of force
AysviL [449]

Answer:

F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.

Explanation:

5 0
3 years ago
Two floors in a building are separated by 4.1 m. People move between the two floors on a set of stairs. (a) Determine the change
Ket [755]

Answer:

a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

Explanation:

Let consider the bottom of the first floor in a building as the zero reference (z = 0\,m). The change in potential energy experimented by a particle (\Delta U_{g}), measured in joules, is:

\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o}) (1)

Where:

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

z_{o}, z_{f} - Initial and final height with respect to zero reference, measured in meters.

Please notice that m\cdot g is the weight of the particle, measured in newtons.

a) If we know that m = 3\,kg, g = 9.807\,\frac{m}{s^{2}}, z_{o} = 0\,m and z_{f} = 4.1\,m, then the change in potential energy is:

\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)

\Delta U_{g} = 120.626\,J

The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) If we know that m\cdot g = 650\,N, z_{o} = 4.1\,m and z_{f} = 0\,m, then the change in potential energy is:

\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)

\Delta U_{g} = -2665\,J

The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

5 0
3 years ago
Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.
Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

\dot{P} = \bar{P}

Where,

\dot{P} = Production of Power

\bar{P} = Consumption of power

Where the production of power would be,

\dot{P} = m \dot{E}\eta

Where,

m = Total mass required

\dot{E} = Energy per Kilogram

\eta =Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

\dot{P} = \bar{P}

m \dot{E}\eta = \bar{P}

Replacing the values we have,

m(8*10^13)(0.45) = 2*10^{12}

Solving for m,

m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}

m = 0.0556 \frac{kg}{s}

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})

m = 1752.14tonnes per year.

8 0
3 years ago
Which is written in scientific notation?
zaharov [31]

Answer:

<h2>C</h2>

Explanation:

2.0 × 10^3 is the correct form for writing any term in scientific notation form.

Comment for understanding anything.

7 0
3 years ago
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