Question

You are hungry and decide to go to your favorite neighborhood fast-food restaurant. You leave your apartment and take the elevator 10 flights down (each flight is 3.0 m) and then go 15 m south to the apartment exit. You then proceed 0.2 km east, turn north, and go 0.1 km to the entrance of the restaurant.Part ADetermine the displacement from your apartment to the restaurant. Use unit vector notation for your answer, being sure to make clear your choice of coordinates.Take the beginning of the journey as the origin, with north being the y-direction, east the x-direction, and the z-axis vertical.Part BHow far did you travel along the path you took from your apartment to the restaurant?Part CWhat is the magnitude of the displacement you calculated in part A?

Answer 1

Answer:

A. (200i + 85j - 30k)m

B.  345m

C. 219.37 m

Explanation:

UP: +VE Z

NORTH: +VE Y

EAST: +VE X

A.

DISPLACEMENT : (0.2*1000 i + (-15+0.1*1000)j + (-3*10)k) m

                            = (200i + 85j - 30k)m

B. total distance = 10*3+15+200+100 = 345m

C.

Magnitude = $\sqrt{{200^{2} } +85^{2} +(-30)^{2}$ = 219.37 m

unit vector = $\frac{200i+85j-30k}{219.4}$