F-mg=ma
F-(12kg)(9.8m/s^2)=(12kg)(1.2m/s^2)
F-117.6N=14.4N
F=132 Newtons
Answer:
#_time = 7.5 10⁴ s
Explanation:
In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.
t =
where t_p is the person's own time in an immobile reference frame,

let's calculate
we assume that the speed of the space station is constant
t_ = 0.99998666657 s
therefore the time change is
Δt = t - t_p
Δt = 1 - 0.9998666657
Δt = 1.3333 10⁻⁵ s
this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s
#_time = 1 / Δt
#_time =
#_time = 7.5 10⁴ s
Mercury,Venus,Earth and Mars
Answer:

Explanation:
#Using the conservation of momentum , momentum before equals momentum after(
.
-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.
Hence:

Hence, the final velocity of the cart and bag is 1.77m/s
Answer:
T = 29.6 N
Explanation:
length of the rope is
L = 18 m
mass of the rope is
m = 12 kg
now we have
mass per unit length of the rope is given as
[te]\lambda = \frac{12 kg}{18 m}[/tex]
now time taken by wave to reach from end to other



now we have


so we will have
