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Paraphin [41]
2 years ago
14

What are the potential out comes of force

Physics
1 answer:
AysviL [449]2 years ago
5 0

Answer:

F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.

Explanation:

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1. A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your
allochka39001 [22]
F-mg=ma
F-(12kg)(9.8m/s^2)=(12kg)(1.2m/s^2)
F-117.6N=14.4N
F=132 Newtons 
5 0
4 years ago
Astronauts aboard the ISS move at about 8000 m/s, relative to us when we look upward.How long does an astronaut need to stay abo
Luba_88 [7]

Answer:

#_time = 7.5 10⁴ s

Explanation:

In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.

            t = \frac{t_p}{ \sqrt{1-  (v/c)^2} }

where t_p is the person's own time in an immobile reference frame,

           t_{p} = t \sqrt{1 - (\frac{v}{c})^2 }

let's calculate

we assume that the speed of the space station is constant

              t_p = 1 \sqrt{1 - \frac{8 \ 10^3}{3 \ 10^8} }

             t_p = 1 \sqrt{1- 2.6666 \ 10^{-5}}

             t_ =  0.99998666657   s

             

therefore the time change is

             Δt = t - t_p

             Δt = 1 - 0.9998666657                  

              Δt = 1.3333 10⁻⁵ s

this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s

               #_time = 1 / Δt

               #_time =\frac{1}{1.3333 \ 10^{-5}}

               #_time = 7.5 10⁴ s

5 0
3 years ago
The four terrestrial planets that have solid, rocky surfaces are
olganol [36]
Mercury,Venus,Earth and Mars
6 0
3 years ago
A grocery shopper tosses a(n) 9.0 kg bag of rice into a stationary 17.4 kg grocery cart. The bag hits the cart with a horizontal
noname [10]

Answer:

V=1.77m/s

Explanation:

#Using the conservation of momentum , momentum before equals momentum after(p=mv).

-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.

Hence:

9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s\\

Hence, the final velocity of the cart and bag is 1.77m/s

7 0
4 years ago
A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

2.7 s = \frac{18}{v}

v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

6.67 = \sqrt{\frac{T}{0.67}}

so we will have

T = 29.6 N

5 0
4 years ago
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