Answer:
The average induced emf in the coil is 0.0286 V
Explanation:
Given;
diameter of the wire, d = 11.2 cm = 0.112 m
initial magnetic field, B₁ = 0.53 T
final magnetic field, B₂ = 0.24 T
time of change in magnetic field, t = 0.1 s
The induced emf in the coil is calculated as;
E = A(dB)/dt
where;
A is area of the coil = πr²
r is the radius of the wire coil = 0.112m / 2 = 0.056 m
A = π(0.056)²
A = 0.00985 m²
E = -0.00985(B₂-B₁)/t
E = 0.00985(B₁-B₂)/t
E = 0.00985(0.53 - 0.24)/0.1
E = 0.00985 (0.29)/ 0.1
E = 0.0286 V
Therefore, the average induced emf in the coil is 0.0286 V
<h2>MULTIPLE CHOICES</h2>
- What is the basic unit of all matter?
- OA neutron
- OB. atom
- OC. electron
- OD. proton
- OE. nucleus
_____
- <u>Atom</u> is the smallest, <u>indivisible unit of a chemical</u> <u>element and the fundamental unit of matter</u>. It consists of a nucleus (neutrons + protons) surrounded by an electron cloud. The <u>atom</u> is the smallest unit of matter that cannot be divided chemically and is a building block with its own set of properties.
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Answer:
Equilibrium quantity = 5
Equilibrium price = 40
Explanation:
given:
p = -x²-3x+80
p = 7x+5
For the equilibrium quantity the price from both the functions will be equal
thus, we have
-x² - 3x + 80 = 7x+5
⇒ x² +3x + 7x + 5 - 80 = 0
⇒x² + 10x - 75 = 0
now solving for x
x²- 5x + 15x -75 = 0
x(x-5) + 15(x-5) = 0
therefore, the two roots of the equation are
x = 5 and x = -15
since the quantity cannot be in negative
therefore, the equilibrium quantity will be = 5
now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation
thus,
p = -(5)² -3(5) + 80 = 40
or
p = 7(5) + 5 = 40
A large elliptical galaxy. Hope this helped
This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. ... When air resistance plays a role, the shape of the object becomes important. In air, a feather and a ball do not fall at the same rate.
