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faust18 [17]
2 years ago
15

Pleas help, I’ll mark as brainliest.

Mathematics
2 answers:
STatiana [176]2 years ago
3 0

Answer:

Step-by-step explanation:

f(4) = -1

g(4) = -2

(f + g)(4) = f(4) + g(4) = -3

Hope that helps!

kiruha [24]2 years ago
3 0

Answer:f(4) = -1g(4) = -2(f + g)(4) = f(4) + g(4) = -3

Step-by-step explanation:

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A triangle has base 7 m and area 17.5 m. What is the height?
Temka [501]
122.5. 

A=b x h/2.     A=122.5  b=7

A x b=h
122.5 x 7 =122.5

5 0
3 years ago
Increase 2850 by 18%
faust18 [17]
3363 it is. That is the answer. The problem would be "2850 + 18%" right. Because that's what I did.<span />
4 0
3 years ago
5x + 1 over 2y2
Oxana [17]

Step-by-step explanation:

So for this question just substitute the value and work out. I thought it it to the power of 2 as I can't tell from the question.

4 0
3 years ago
Katie and her brother are both writing a report. Katie write 7/8 of her report and her brother wrote 3/7 of his report. What is
skad [1K]

Answer:

Answer is 25/56

Step-by-step explanation:

Given that

Katie and her brother are both writing a report. Katie write 7/8 of her report and her brother wrote 3/7 of his report

TO compare these two fractions we have to make both of them have the same denominator.

We find that as such the two fractions have denominators as 7 and 8 and hence Least common multiple is 56

LEt us make equivalent fractions

7/8 = 49/56

3/7=24/56

Difference i.e. Katie wrote more than her brother = 49/56-24/56

=25/56

4 0
3 years ago
To evaluate log2(3), Autumn reasoned that since log2(2) = 1 and log2(4) = 2, log2(3) must be the average of 1 and 2 and therefor
geniusboy [140]

Answer:

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

Step-by-step explanation:

Given:

log₂(2) = 1

log₂(4) = 2

To evaluate :  log₂(3)

Now,

we know that

logₓ(y) = \frac{\log(y)}{\log(x)}        (Here the log has same base in the numerator and the denominator i.e 10)

therefore,

log₂(3) =  \frac{\log(3)}{\log(2)}

also,

log(2) = 0.3010

log(3) = 0.4771

thus,

log₂(3) =  \frac{0.4771}{0.3010}

or

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

7 0
4 years ago
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