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3 years ago

I need help cause uh i’m dumb

Mathematics

1 answer:

ozzi3 years ago

8 0

Answer:

$650

Step-by-step explanation:

9100-4500 = 4550

14-7 7

= 650

=$650

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Which of the following graphs shows the preimage P(x)=x^2 and the image I(x)=P(1/3x)?

Ksju [112]

Answer:

The picture with the widest graph in red

Step-by-step explanation:

The graph P(x) is the parent graph for all quadratic functions. It has a vertex of (0,0) and has the following points:

x f(x)

-2 4

-1 1

0 0

1 1

2 4

The image of l(x) = P(1/3x) changes the points of the function to

x f(x)

-2/3 4/9

-1/3 1/9

0 0

1/3 1/9

2/3 4/9

This makes the graph much wider. The graph with the widest red graph is the graph.

7 0

3 years ago

Read 2 more answers

25/50 as a percentage

kakasveta [241]

50%, if you put it into a calculator 25/50 gives you .50, move decimal 2 times to the right to get 50.

3 0

2 years ago

Let f(x)=x+3 and g(x)=1/x. The graph of (f*g)(x) is shown below.

Vlad [161]

For this case we have the following functions:
$f (x) = x + 3

g (x) = 1 / x$ When composing the functions we have:
$(fog) (x) = f (g (x))
$
Substituting values we have:
$(fog) (x) = ((1 / x) +3)
$
Rewriting:
$(fog) (x) = 1 / x + 3
$
The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3

3 0

3 years ago

1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

$\ln|y| = x - \ln|x+1| + C$

When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

and the bounded region is the set

$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

7 0

2 years ago

John can fly his airplane 2,800 miles with a wind speed of 50 mph. In the same time he can travel 2,400 miles against the wind.

andreev551 [17]

Answer:

650 mph

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers