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agasfer [191]
4 years ago
14

I need help cause uh i’m dumb

Mathematics
1 answer:
ozzi4 years ago
8 0

Answer:

$650

Step-by-step explanation:

<u>9100-4500</u>     = <u>4550</u>

    14-7                  7

= <u>650</u>

     1

=$650

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a person invested $6700 for one year, part at 8%, part at 10%, and the remainder at 12%. the total annual income from these inve
lukranit [14]

Answer:

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

Step-by-step explanation:

step 1

Let

x-----> the amount invested at 8% rate

y-----> the amount invested at 10% rate

z-----> the amount invested at 12% rate

z=(x+y)+300 ----> equation A

x+y+z=6,700 ----> equation B

substitute equation A in equation B

x+y+(x+y+300)=6,700

2x+2y=6,400

x+y=3,200 -----> equation C

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=1\ year\\ P=\$6,700\\ I=\$716

substitute in the formula above

716=x(0.08)+y(0.10)+z(0.12)

substitute equation A

716=x(0.08)+y(0.10)+(x+y+300)(0.12)

716=0.08x+0.10y+0.12x+0.12y+36

716=0.20x+0.22y+36

0.20x+0.22y=680  -----> equation D

step 2

Solve the system of equations

x+y=3,200 -----> equation C

0.20x+0.22y=680  -----> equation D

Solve the system by graphing

The solution is the point (1,200,2,000)

see the attached figure

Find the value of z

z=(x+y)+300

z=(1,200+2,000)+300=3.500

therefore

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

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4 years ago
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