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SVEN [57.7K]
4 years ago
15

1. 12(x−4)= 2. −8(y+12)=3. −(x−11)=

Mathematics
1 answer:
Natali5045456 [20]4 years ago
8 0

Answer:

12x-48

-8y-96

-x+11

Step-by-step explanation:

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Which statement is false? A. (−2)×5<(−20) B. (−2)×(−5)>(−25) C. 2×5>(−25) D. 2×(−5)<20
natali 33 [55]

Answer:

(−2)×5<(−20)

Step-by-step explanation:

Evaluating the options given :

(−2)×5<(−20)

Open the bracket

- 10 < - 20 (false) ` This expression isn't true

(−2)×(−5)>(−25)

Open the bracket

10 > - 25 (true)

2×5>(−25)

Open the bracket

10 > - 25 (true)

2×(−5)<20

Open the bracket

- 10 < 20

4 0
3 years ago
Hey can you help me fast!!!
scZoUnD [109]

Answer:

Area= 4 ft²

Step-by-step explanation:

Area= (2)(2)

multiply 2 × 2= 4

Area= 4 ft²

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4 0
3 years ago
4/5 dived by 3/4<br><br> Please help
Leto [7]

Answer:

1 1\15

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more
Llana [10]

Given :

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.

To Find :

How many tickets were sold to students.

Solution :

Ticket sold to teachers, T = 563 .

Ticket sold to parents, P = 904 .

Let, ticket sold to students are S.

Now, it is given that :

S = T + 904

S = 563 + 904

S = 1467  students

Therefore, tickets sold to students are 1467 .

Hence, this is the required solution.

6 0
3 years ago
What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?
sveta [45]

Answer:       A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

15+45=60

Relative frequency of people of A in Group 1 is given by

\frac{15}{60}=0.25

Relative frequency of people of B in Group 1 is given by

\frac{45}{60}=0.75

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

20+25=45

Relative frequency of people of A in Group 2 is given by

\frac{20}{45}=0.44

Relative frequency of people of B in Group 2 is given by

\frac{25}{45}=0.56

Hence,        A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

6 0
3 years ago
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