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SVEN [57.7K]
4 years ago
15

1. 12(x−4)= 2. −8(y+12)=3. −(x−11)=

Mathematics
1 answer:
Natali5045456 [20]4 years ago
8 0

Answer:

12x-48

-8y-96

-x+11

Step-by-step explanation:

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Solve for y
tresset_1 [31]

Answer:

y= -5/4x+2

Step-by-step explanation:

probably wrong but it definitely is one of the bottom two answers

6 0
3 years ago
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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
alexdok [17]
Anything to the 0th power is always equal to one.
3 0
4 years ago
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The hypotenuse of a right triangle measures 10 inches and the side opposite to <0 one of the non right angles is 5 inches lon
AfilCa [17]
Sin = Opposite/ Hypotenuse
Sin (theta)= 5/10
Sin^-1(5/10)=30
theta=30
5 0
3 years ago
Ill give brainliest please help with this algebra!!
creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple.  Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20.  If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent.  If it is instead a coefficient though, then this would be the answer to it.

8 0
3 years ago
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If the discriminant of a quadratic equation is 6, how many solutions does the equations have?
rjkz [21]
If d=6, there are two real solutions.

Rule if d=discriminant:

d>0, two real solutions

d=0, one real solution

d<0, no real solutions  (but there are two imaginary solutions)
6 0
3 years ago
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