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4 years ago

1/7 x 2/3 whats the answer? show ur work

Mathematics

2 answers:

Mekhanik [1.2K]4 years ago

4 0

Answer:

Step-by-step explanation:

1/7×2/3=2/21

Solution with Steps

1/7×2/3=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

1×2 and 7×3=2/21

This fraction cannot be reduced.

Therefore:

1/7×2/3=2/21

Solution by Formulas

Apply the fractions formula for multiplication, to

1/7×2/3

and solve

1×2 and 7×3

=2/21

Llana [10]4 years ago

3 0

Answer:

1/7 × 2/3 is 2/21

becuase, if you times the numerators, which are the top numbers; and then the denominators which are the bottom numbers; like if you multiply 1×2 you get 2 and 7×3 is 21.

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We're told that

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where the last fact is due to the law of total probability:

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$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

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We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

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$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

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