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Elena-2011 [213]
3 years ago
8

Determine the quadrant(s) in which (x, y) could be located. (Select all that apply.) x > 0 and y < 0 Quadrant I Quadrant I

I Quadrant III Quadrant IV none of these
Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

Answer:

Quadrant IV

Step-by-step explanation:

If x is greater than 0, then it will remain on the right side, on quadrants I and IV. If y is less than 0, then it will be on the bottom, so we are left with quadrant IV:

x is greater than 0, so all possible values are positive

y is less than 0, so all possible values are negative

(x,-y)

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Which of the following statements is true?
Inessa05 [86]

Answer: the number -5 is a real number

Real numbers are both negative and positive numbers. -5 is a negative number. Since real numbers include negative numbers, -5 is the answer.

Hope this helps!

7 0
3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Pavel [41]

\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Explanation:</h2>

Using the quadratic formula:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

8 0
3 years ago
1 point
77julia77 [94]

Answer:

A negative integer

Step-by-step explanation:

3x - 2(5x+12) - 32 = 0

3x - 10x - 24 - 32 = 0

-7x -56 = 0

-7x = 56, x = -8

y = 5(-8) + 12, y = -28

6 0
3 years ago
21.50 x y = 225<br> what is y?<br> I need help, please
garik1379 [7]

Answer:

10.5

Step-by-step explanation:

225÷21.50

=10.46511

=10.5(3sf)

4 0
3 years ago
Read 2 more answers
T to the power of 2 equals 25
-BARSIC- [3]
5 to the power of 2 is 25
3 0
3 years ago
Read 2 more answers
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