13.45 will be the answer
since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2
this will then be 10^2 + 9^2 = c^2
181=c^2
c=13.45 :)
Answer:
0.05 AU corresponds to the 0.0769 Inches(<em>This calculation is not possible in real time world)</em>
Step-by-step explanation:
Given:
0.65 corresponds to 1 inch
To Find:
0.05 AU corresponds to how many inches.
Solution:
<em>The AU is astronomical unit which is preferred as the mean distance between earth and sun.</em>
<em>AU is too big unit and used in space distance calculation.</em>
But here for mathematical calculation,
0.65 AU corresponds to 1 inch
then 0.05 AU corresponds to x inch(es)
Now cross multiplying the quantities we get ,
0.65x=0.05*1
x=0.05/0.65
x=0.0769 inches corresponds to 0.05 AU
(Preferred for this example only)
<em>(Remember that this calculation is hypothetical and practically incorrect to use it).</em>
<em />
Answer:
Third answer! Data varies!
Answer:
3.84% probability that it has a low birth weight
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 3466, \sigma = 546](https://tex.z-dn.net/?f=%5Cmu%20%3D%203466%2C%20%5Csigma%20%3D%20546)
If we randomly select a baby, what is the probability that it has a low birth weight?
This is the pvalue of Z when X = 2500. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{2500 - 3466}{546}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B2500%20-%203466%7D%7B546%7D)
![Z = -1.77](https://tex.z-dn.net/?f=Z%20%3D%20-1.77)
has a pvalue of 0.0384
3.84% probability that it has a low birth weight