Find the volume of the cylinder in terms of pi.
1 answer:
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The point (3, 2) is the solution to given system of equations
<em><u>Solution:</u></em>
Given that system of equations are:
------ eqn 1
------- eqn 2
From eqn 2,
y = 2x - 4
Substitute y = 2x - 4 in eqn 1
Let us solve the above equation by quadratic formula,
Using the Quadratic Formula for where a = 5, b = -16, and c = 3
The discriminant so, there are two real roots.
Substitute for x = 0.2 and x = 3 in 2x - y = 4
<em><u>when x = 3</u></em>
2(3) - y = 4
6 - y = 4
y = 2
<em><u>when x = 0.2</u></em>
2(0.2) - y = 4
0.4 - y = 4
y = 0.4 - 4
y = -3.6
Thus Option D is correct The point is (3, 2)
Check the picture below.
Answer: x = 5π/6
Explanation:
1) Given function:
2) x-intercept are the roots of the function, i.e. the solution to y = 0
3) to find when y = 0, you can either solve the equation or look at the graph.
4) Solving the equation you get:
y = 0 ⇒ tan(x - 5π/6) = 0 ⇒ x - 5π/6 = arctan(0)
arctan(0) is the angle whose tangent is zero,so this is 0
⇒ x - 5π/6 = 0 ⇒ x = 5π/6.
Then, one example of an x-intercept is x = 5π/6, which means that when x = 5π/6, the value of the function is 0.
Since, the tangent function is a periodic function, there are infinite x-intecepts, that is why the questions asks for one example and not all the values.
You can verify by replacing the value x = 5π/6 in the given function:
y = tan (5π/6 - 5π/6) = tan(0) = 0.
Explanation:
1) Given function:
2) x-intercept are the roots of the function, i.e. the solution to y = 0
3) to find when y = 0, you can either solve the equation or look at the graph.
4) Solving the equation you get:
y = 0 ⇒ tan(x - 5π/6) = 0 ⇒ x - 5π/6 = arctan(0)
arctan(0) is the angle whose tangent is zero,so this is 0
⇒ x - 5π/6 = 0 ⇒ x = 5π/6.
Then, one example of an x-intercept is x = 5π/6, which means that when x = 5π/6, the value of the function is 0.
Since, the tangent function is a periodic function, there are infinite x-intecepts, that is why the questions asks for one example and not all the values.
You can verify by replacing the value x = 5π/6 in the given function:
y = tan (5π/6 - 5π/6) = tan(0) = 0.