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Alexxx [7]
3 years ago
12

Someone know how to do this?: 6x2+18x=0

Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0
The answer to the question is: Yes.

Explanation:  It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.

Since I'm here already, here is the solution to this one:

6x² + 18x = 0

Divide each side of the equation by 6 :

x² + 3x = 0

Factor the left side:

x(x+ 3) = 0

This statement is true if x=0 or if x=3.

The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
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Factor the polynomial
Art [367]

Find the GCF (Greatest Common Factor)

GCF = 2x

Factor out the GCF (Write the GCF first and then, in parentheses, divide each term by the GCF.)

2x (2x^3/2x + 4x^2/2x + 6x/2x)

Simplify each term in parentheses

-2x(x^2 + 2x + 3)

<u>Answer D. -2(x^2 + 2x + 3)</u>

7 0
3 years ago
Rewrite in simplest terms: -4(5v – 3v – 6) – 9v
julsineya [31]

Answer:

-4 (5v -3v -6) -9v (use the distributive property)

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-17v +24

3 0
2 years ago
Read 2 more answers
A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0
2 years ago
ANSWER ASAP!
morpeh [17]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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Rough surfaces

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