Answer:
Step-by-step explanation:
solve each inequality:
A : x+6<8 , x<-8-6 , x<-14
B: x+4≥-6 , x≥-10
C: x-3>-10 , x>-7
D:x≤-9
since -12 is on the left side of the number line then x≤ -9 would be the solution
Answer:
1,778
Step-by-step explanation:
Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.
Truck A's cost for 10 years is ...
A = C+600 +(0.06)(2.25)(10X) -(S+200)
Truck B's cost for 10 years is ...
B = C +(0.07)(2.25)(10X) -S
We want to find X such that Truck A's cost is lower, so ...
C -S +1.35X +400 < C -S +1.575X
400 < 0.225X
1777 7/9 < X
1778 miles driven per year (or more) makes Truck A a better option.
Answer:
B/2
Step-by-step explanation:
The table mentions that the time actually starts from the end of the first month, so it cannot be graph one, which starts from 0.
Also, we can see that the values are decreasing over time, meaning it cannot be graph 3, which shows an increase.
thus, we settle the Answer as Graph 2, which satisfies all the needs.
Hope this helps.
