Two acute angles is the least amount.
The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
Answer:
+1 is the potential root of the function.
Step-by-step explanation:
Given;
p(x) = x⁴ + 22x⁴ – 16x - 12
A potential root of the function is zero of the function. That is a potential root will reduce the function to zero or close to zero.
To determine this, we test each of the root given;
p(6) = (6)⁴ + 22(6)⁴ - 16(6) - 12 = 29700
p(3) = (3)⁴ + 22(3)⁴ - 16(3) - 12 = 1803
p(1) = (1)⁴ + 22(1)⁴ - 16(1) - 12 = -5
p(8) = (8)⁴ + 22(8)⁴ - 16(8) - 12 = 94068
The only number that reduces the function close to zero is +1, then +1 is the potential root of the function.
Answer:
number 2
Step-by-step explanation:
