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nataly862011 [7]

2 years ago

6

Dale bought 6 CDs that were each the same price. Including sales tax, he paid a total of $98.40. Each CD had a tax of $1.10. Wha

t was the price of each CD
before tax?
?

1 answer:

Digiron [165]2 years ago

4 0

Answer:

If you multiply the 6 to the $1.10 you get 6.60. Then subtract the 98.40 from the 6.60 and you get 91.80.

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Find the missing side of the right triangle

vlada-n [284]

Answer:

$a {}^{2} + b {}^{2} = c {}^{2} \\ b {}^{2} = \sqrt{c {}^{2} - a {}^{2} } \\ b = \sqrt{14 {}^{2} - 3 {}^{2} } \\ b = \sqrt{196 - 9} \\ b = \sqrt{187} \\ b = 13.7$

I hope this help

6 0

2 years ago

Whats an example of a linear relationship?

kramer

It is a straight line in a graphical format.

5 0

2 years ago

Read 2 more answers

What is the image point of ( 4 , − 6 ) (4,−6) after a translation right 5 units and up 4 units?

Stella [2.4K]

Answer:

(9,-2)

Step-by-step explanation:

5 is the x coordinate, and 4 is the y coordinate. When you go right a certain amount of units, you add those units to your x coordinate. If you were to go left a certain amount of units, you'd subtract them. Since we're going right, 5 + 4 = 9. When you go up a certain amount of units, you add those units to you y coordinate. If you were to go down a certain amount of units, you'd subtract them. Since we're going up, -6 + 4 = -2. So, x = 9 and y = -2, or (9,-2)

3 0

3 years ago

Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical aptitude) to 5 (high m

morpeh [17]

The question is incomplete. Here is the complete question.

Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical aptitude) to 5 (high musical aptitude). This year's results were shown in the figure below.

The average (mean) aptitude score:

The median aptitude score:

Answer: mean: 2.73

median: 3

Step-by-step explanation: <u>Mean</u> is the average number of a set of numbers.

The table below shows a frequency of students to each score of the test. To calculate mean with a frequency table, do the following:

$mean=\frac{\Sigma (score*frequency)}{\Sigma frequency}$

$mean=\frac{0*1+1*5+2*0+3*3+4*3+5*3}{1+5+0+3+3+3}$

mean = 2.73

<u>Median</u> is the middle term of a set of data.

When there is a frequency table, median is calculated as:

1) First, determine the total number of observations (n).

For this table, n = 15

2) Because n is odd, find the position of the median using:

$position=\frac{n+1}{2}$

position = 8th

3) The median will be in the 8th position. To find the position, we add the frequencies and in doing so, we notice the position we want is in the score 3 category. So, the median for this frequency table is 3.

<u>Average score</u> of a musical aptitude test is <u>2.73</u> and median is 3

8 0

2 years ago

Which equation describes a line that passes through (-6, 8) and is parallel to the line described by y = 2x − 4?

AleksandrR [38]

Answer:

hey, there!

Step-by-step explanation:

The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4

The equation for point (-6,8) is,

(y-8)= m1(x+6)...........(i)

and given equation is y = 2x-4............(ii)

Now, from equation (ii).

slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.

Now, For perpendicular,

m1×m2= -1

m1×2= -1

Therefore, m1 = -1/2.

Putting, the value of m1 in equation (i).

(y-8) = -1/2×(x+6)

2(y-8)= -1(x+6)

2y - 16 = -x -6

x+2y-10 = 0......... is the required equation.

Hope it helps...

6 0

2 years ago