Answer:
The gradient of the straight line that passes through (2, 6) and (6, 12) is 
.
Step-by-step explanation:
Mathematically speaking, lines are represented by following first-order polynomials of the form:
(1)
Where:
- Independent variable.
- Dependent variable.
- Slope.
- Intercept.
The gradient of the function is represented by the first derivative of the function:
Then, we conclude that the gradient of the staight line is the slope. According to Euclidean Geometry, a line can be form after knowing the locations of two distinct points on plane. By definition of secant line, we calculate the slope:
(2)
Where:
, 
- Coordinates of point A.
, 
- Coordinates of point B.
If we know that 
and 
, then the gradient of the straight line is:
The gradient of the straight line that passes through (2, 6) and (6, 12) is .
Answer:
Step-by-step explanation:
Nathan's score is 11 less than 2 times Zac's score.
Let Z points be Zac's score and N points be Natan's score. then
2 times Zac's score = 2Z
11 less than 2 times Zac's score = 2Z -11
So, N = 2Z - 11
1. If Z=6, then 
2. If Z=7, then 
3. If Z=8, then 
4. If Z=9, then 
Thus, four other possibilities are
It’s beautiful because if you set up the problem as proportion and you put 3/106 over to you would have to multiply by 2×3 to get a six and 1×2 to get it to so it’s 2 mph
Answer:
44.94
Step-by-step explanation:
Use trigonometric ratios to find the unknown side.
Since you are given the adjacent side and the opposite side is in question, use the tangent ratio.
tan(x) = opposite/adjacent
Replace the variables with given values.
tan(59) = x/27
Isolate the variable.
27tan(59) = x
Use a calculator to evaluate the answer.
x = 27tan(59) ≈ 44.94
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