If a baker doubles a recipe that calls for 6-2/3 cups of flour. How many cups will be needed in all?
2 answers:
Hey there!
The easiest way I could think to do this is by converting your mixed number to an improper fraction and multiplying the fraction by 2, or 2 over 1.
To multiply fractions, you can just multiply the numerators and denominators and simplify, if applicable.
Since you can't simplify this fraction in its improper form, just convert it back into a mixed number.
So, your answer will be
.
Hope this helped you out! :-)
The easiest way I could think to do this is by converting your mixed number to an improper fraction and multiplying the fraction by 2, or 2 over 1.
To multiply fractions, you can just multiply the numerators and denominators and simplify, if applicable.
Since you can't simplify this fraction in its improper form, just convert it back into a mixed number.
So, your answer will be
Hope this helped you out! :-)
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The statement that does not match the others is the one at lower right.
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The barn's volume can be decomposed into a rectangular prism and a triangular one. Thus the <em>upper right</em> expression is a true represenation of the barn's volume:
... Volume of triangular prism + Volume of rectangular prism
The volume of a <em>rectangular prism</em> is the product of its dimensions. The dimensions of the rectangular prism portion of the barn's volume are a, b, c, so the volume of that portion is ...
... Volume of rectangular prism = a·b·c
The volume of a <em>triangular prism</em> is the area of the triangular base multiplied by the length of the prism. Here, the triangular base has base dimension b and height (d-c), so its area is ...
... Area of triangular barn end = (1/2)b(d-c)
Since the length of the barn is "a", the volume of the triangular prism is ...
... Volume of triangular prism = (1/2)b(d-c)a = (1/2)·a·b·(d-c)
The <em>total volume</em> is the sum of the volumes of the parts ...
... a·b·c + (1/2)·a·b·(d-c) . . . . . . matches the <em>upper right</em> selection
This can be factored by removing a·b to outside parentheses:
... a·b·((1/2)·(d-c) + c) . . . . . . . . . matches the <em>lower left</em> selection
___
Since the two left selections match the one at upper right, the odd one is the one at lower left.
