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lisabon 2012 [21]
3 years ago
7

4.

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Answer:

Number of multiple-choice questions = x = 35 questions

Number of open-ended questions = y = 3 questions

Step-by-step explanation:

Let

Number of multiple-choice questions = x

Number of open-ended questions = y

x + y = 38 (1)

4x + 20y = 200 (2)

From (1)

x = 38 - y

Substitute x = 38 - y into (2)

4x + 20y = 200

4(38 - y) + 20y = 200

152 - 4y + 20y = 200

- 4y + 20y = 200 - 152

16y = 48

y = 48/16

y = 3

Substitute y = 3 into (1)

x + y = 38

x + 3 = 38

x = 38 - 3

x = 35

Number of multiple-choice questions = x = 35 questions

Number of open-ended questions = y = 3 questions

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doris tiene en su cartera billetes de $10 y de $20.si en total tienen 25 billetes y $330 ¿cuantos billetes tiene cada uno?
inessss [21]

Answer:

8 billetes de 20

17 billetes de 10  

Step-by-step explanation:

4 0
3 years ago
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Find the perimeter of quadrilateral ABCD with vertices A=(1,1) B=(4,4) C=(7,1) D=(4,-2). Explain your answer.​
Vanyuwa [196]

we have the coordinates of ABCD

there are 2 ways of doing this one is you find the distance of ab, bc, cd and da and then add the answers together. there is another way but i dont remember it properly so i am just gonna do it this way

distance between 2 point = \sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

AB

d = \sqrt {(4 - 1)^2 + (4 - 1)^2}

d = \sqrt {(3)^2 + (3)^2}

d = \sqrt {9 + 9}

d = \sqrt 18

AB = 4.24

now repeat the same with all

BC= 4.24

CD= 4.24

DA= 4.24

so its a square with all the same sides so perimeter is 4 x 4.24

perimeter is 16.96

hope this helps

mark me as brainliest please

3 0
3 years ago
Among freshman at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 10
lina2011 [118]

Answer:

a) 6.68th percentile

b) 617.5 points

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 550, \sigma = 100

a) A student who scored 400 on the Math SAT was at the ______ th percentile of the score distribution.

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 550}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

So this student is in the 6.68th percentile.

b) To be at the 75th percentile of the distribution, a student needed a score of about ______ points on the Math SAT.

He needs a score of X when Z has a pvalue of 0.75. So X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 550}{100}

X - 550 = 0.675*100

X = 617.5

6 0
3 years ago
What is the equation of the line in standard form?<br> 3x−y=−6 3x + y = 6 x + 6y = 9 x−6y=−9
lisabon 2012 [21]

The standard form: Ax + By = C

3x - y = -6  YES - A = 3, B = -1, C = -6

3x + y = 6   YES - A = 3, B = 1, C = 6

x + 6y = 9   YES - A = 1, B = 6, C = 9

x - 6y = -9   YES - A = 1, B = -6, C = -9

8 0
3 years ago
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is
Lerok [7]

Answer: possible values of Range will be values that are >=91 or <=998

Step-by-step explanation:

Given that :

Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.

Therefore,

given that the smallest value in set Q is a one digit number :

Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)

Also, the largest value in Set Q is a three digit value:

Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).

Therefore, the possible values of the range in SET Q:

The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998

The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91

5 0
3 years ago
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