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2 years ago

What is the product of -15*(-1/2)

Mathematics

2 answers:

kaheart [24]2 years ago

6 0

Hello!

<h2>"+"- sum</h2><h2>"*"-product </h2><h2>"-"- difference</h2>

$-15*(-\frac{-1}{2} )$

$(\frac{-15}{1}) (\frac{-1}{2})$

$\frac{(-15)(-1)}{(1)(2)}$

$=\frac{15}{2}$

<em>You can also round up to the nearest tenths is 7.5 to 8.0</em>

Hope this helps! Thank you for posting your question at here on Brainly.

-Charlie

seraphim [82]2 years ago

4 0

what is the product of -15*(-1/2)

-15 * (-1/2)

-15 * -0.5 =

7.5

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_____ + 5 3/4 = 9 5/8<br>please help you will get 75 points

LuckyWell [14K]

Answer:

3 7/8

Step-by-step explanation:

_____ + 5 3/4 = 9 5/8

x + 5 3/4 = 9 5/8

Subtract 5 3/4 from each side

x + 5 3/4 - 5 3/4 = 9 5/8 - 5 3/4

x = 9 5/8 - 5 3/4

Get a common denominator of 8

5 3/4 *2/2 = 5 6/8

x = 9 5/8 - 5 6/8

We need to borrow 1 from the 9 in the form of 8/8

x= 8 + 8/8+ 5/8 - 5 6/8

x = 8 13/8 - 5 6/8

= 3 7/8

7 0

2 years ago

Read 2 more answers

Suppose p(a) = 0.40 and p(a 

sveticcg [70]

Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$

For parts (a) and (b), you're given everything you need to determine $P(B)$ .

For part (c), if $A$ and $B$ are mutually exclusive, then $P(A\cap B)=0$ , so $P(A\cup B)=P(A)+P(B)$ . If the given probability is $P(A\cup B)=0.55$ , then you can find $P(B)=0.15$ . But if this given probability is for the intersection, finding $P(B)$ is impossible.

For part (d), if $A$ and $B$ are independent, then $P(A\cap B)=P(A)\cdot P(B)$ .

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2 years ago

Solve for x. Can somebody help me? I don’t understand how to do this.

Basile [38]

$-1=\dfrac{5+x}{6}\\\\-6=5+x\\\\x=-11$