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harkovskaia [24]
3 years ago
7

308 miles in 7 hours. Find the

Mathematics
1 answer:
Ronch [10]3 years ago
4 0

Answer:

They did 44 miles per hour

Step-by-step explanation:

308 / 7 = 44

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For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative
trapecia [35]

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = -8(1)+0(3)+1(-3)\\= -11

Projection of U on V =\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }

Similarly projection of V on U

=\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }

4 0
3 years ago
I need a little help! Can someone check my work? It's a written response with linear systems.
andreyandreev [35.5K]

Answer:

I'd say you need to be more specific.

Step-by-step explanation:

"Different" doesn't tell you much.

Consider the equations ...

  • y = 2x + 1
  • 4x - 2y = -2

These equations are "different", but they are <em>dependent</em>.

_____

I'd mentally (or actually) put the equations in the same form and compare the coefficients of x and y. If they have different ratios, the system is independent and consistent.

If they have the same ratio, the system will not have a single solution. Whether there is no solution or an infinite number of solutions depends on the constant, which I would examine next.

The system above can be put in the form

  • 2x -y = -1
  • 4x -2y = -2

In both cases, the ratio of the x coefficient to the y coefficient is 2/-1 = 4/-2 = -2. This means the lines are at least parallel, if not identical. The numbers in the second equation are all 2 times the numbers in the first equation, so the equations are <em>dependent</em>, and there are an infinite number of solutions. (Both describe the same line.)

If the second equation were 4x -2y = 1, then the two equations would be describing parallel lines, so they would be called <em>inconsistent</em>.

5 0
3 years ago
6. Rose used 0.9 meter of a piece of cloth for her doll's dress. Write 0.9 i
ira [324]

Answer:

hey man I'm contented even I'm ok thank to be a little late today so I will be there in a few min amu na Ang time you want me to bring anything to do it tomorrow I have no bank of america in the morning to lihog check it out w w ok I will be kmusta Ang Exam sa company that charges if you are not serious to help the poor people you put it on the list of the night before I go to work and I'm contented what I am going out of town and I believe you that you can help with anything else di tawo sa company I can't wait to meet her and I believe you that charges if you have a chance can you help my ara ara ara ara ara ara ara it is big money for the weekend of

3 0
2 years ago
The length of a rectangle is 4 m less than the diagonal and the width is 5 m less than the diagonal. If the area is 82 m^2, how
nikklg [1K]

I hate rounding.

Let's call the diagonal x.  It's the hypotenuse of the right triangle whose legs are the rectangle sides.

According to the problem we have a length x-4 and a width x-5 and an area

82 = (x-4)(x-5)

82 = x^2 - 9x + 20

0 = x^2 - 9x - 62

That one doesn't seem to factor so we go to the quadratic formula

x = \frac 1 2(9 \pm \sqrt{9^2-4(62)}) = \frac 1 2(9 \pm \sqrt{329})

Only the positive value makes any sense for this problem, so we conclude

x = \frac 1 2(9 \pm \sqrt{329})

That's the exact answer.  Did I mention I hate rounding?  That's about

x = 13.6 meters

Answer: 13.6

----------

It's not clear to me this problem is consistent.  By the Pythagorean Theorem the diagonal satisfies

x^2 = (x-4)^2 + (x-5)^2

which works out to

x=9 \pm 2\sqrt{10}

That's not consistent with the first answer; this problem really has no solution.  Tell your teacher to get better material.

5 0
2 years ago
I don't know how to do this. If you can help that would be awesome.
AfilCa [17]
Use the volume of a cylinder equation, V = pi*r^2*h to find the volume of the cylinder. To find the answer to the second one, find the volume of the square and subtract the volume of the cylinder from it.
4 0
3 years ago
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