308 miles in 7 hours. Find the

For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative

trapecia [35]

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = $-8(1)+0(3)+1(-3)\\= -11$

Projection of U on V = $\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }$

Similarly projection of V on U

= $\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }$

4 0

3 years ago

I need a little help! Can someone check my work? It's a written response with linear systems.

andreyandreev [35.5K]

Answer:

I'd say you need to be more specific.

Step-by-step explanation:

"Different" doesn't tell you much.

Consider the equations ...

y = 2x + 1
4x - 2y = -2

These equations are "different", but they are dependent.

_____

I'd mentally (or actually) put the equations in the same form and compare the coefficients of x and y. If they have different ratios, the system is independent and consistent.

If they have the same ratio, the system will not have a single solution. Whether there is no solution or an infinite number of solutions depends on the constant, which I would examine next.

The system above can be put in the form

2x -y = -1
4x -2y = -2

In both cases, the ratio of the x coefficient to the y coefficient is 2/-1 = 4/-2 = -2. This means the lines are at least parallel, if not identical. The numbers in the second equation are all 2 times the numbers in the first equation, so the equations are dependent, and there are an infinite number of solutions. (Both describe the same line.)

If the second equation were 4x -2y = 1, then the two equations would be describing parallel lines, so they would be called inconsistent.

5 0

3 years ago

6. Rose used 0.9 meter of a piece of cloth for her doll's dress. Write 0.9 i

ira [324]

Answer:

hey man I'm contented even I'm ok thank to be a little late today so I will be there in a few min amu na Ang time you want me to bring anything to do it tomorrow I have no bank of america in the morning to lihog check it out w w ok I will be kmusta Ang Exam sa company that charges if you are not serious to help the poor people you put it on the list of the night before I go to work and I'm contented what I am going out of town and I believe you that you can help with anything else di tawo sa company I can't wait to meet her and I believe you that charges if you have a chance can you help my ara ara ara ara ara ara ara it is big money for the weekend of

3 0

2 years ago

The length of a rectangle is 4 m less than the diagonal and the width is 5 m less than the diagonal. If the area is 82 m^2, how

nikklg [1K]

I hate rounding.

Let's call the diagonal x. It's the hypotenuse of the right triangle whose legs are the rectangle sides.

According to the problem we have a length x-4 and a width x-5 and an area

82 = (x-4)(x-5)

82 = x^2 - 9x + 20

0 = x^2 - 9x - 62

That one doesn't seem to factor so we go to the quadratic formula

$x = \frac 1 2(9 \pm \sqrt{9^2-4(62)}) = \frac 1 2(9 \pm \sqrt{329})$

Only the positive value makes any sense for this problem, so we conclude

$x = \frac 1 2(9 \pm \sqrt{329})$

That's the exact answer. Did I mention I hate rounding? That's about

x = 13.6 meters

Answer: 13.6

----------

It's not clear to me this problem is consistent. By the Pythagorean Theorem the diagonal satisfies

$x^2 = (x-4)^2 + (x-5)^2$

which works out to

$x=9 \pm 2\sqrt{10}$

That's not consistent with the first answer; this problem really has no solution. Tell your teacher to get better material.

5 0

2 years ago

I don't know how to do this. If you can help that would be awesome.

AfilCa [17]

Use the volume of a cylinder equation, V = pi*r^2*h to find the volume of the cylinder. To find the answer to the second one, find the volume of the square and subtract the volume of the cylinder from it.

4 0

3 years ago