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MArishka [77]
3 years ago
8

Which best defines a pioneer species?

Chemistry
2 answers:
algol133 years ago
5 0

Answer:

The third one is the correct answer

Explanation:

velikii [3]3 years ago
4 0

Answer:

It would have to be C: the first species to populate an uninhabited area

Explanation:

The meaning of Pioneer species is: the first species to populate an uninhabited area

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Which one of the following substances should exhibit hydrogen bonding in the liquid state?
Sonja [21]

Answer:

What are the following substances?

Explanation:

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3 years ago
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Round the following answer correctly. 5.40m x 3.21m x 1.871m = 32.431914 m^3
Klio2033 [76]
The answer is 32.43 because when you round the number next to the hunthers place (witch in this problem would be the 1) has to be 5 or hight to raise the number to the left of it and if it is lower you just take the two number and that is your answer.
5 0
3 years ago
URGENT!??! Please hurry ?!!!
Montano1993 [528]

Answer:

Table which was completed correctly is :

B) Answer choice G

Explanation:

Metals : Most of the elements in the periodic comes in the category of metal. They are found in left and middle of periodic table.

<u>List of metals </u>

Alkali : Li , Na , K ,Rb , Cs ,Fr

Alkaline : Be , Mg , Ca , Sr ,Ba ,Ra

Transition : Sc ,Ti ,V ,Cr ,Mn , Fe , Co, Ni Cu , Zn ,Y ,Zr ,Nb ,Mo ,Tc ,Ru , Rh , Pd , Ag , Cd , In , Sn, La ,Hf ,Ta ,W ,Re ,Os ,Ir ,Pt ,Au ,Hg

Non -Metals: Most of the p-block element are non metal. They are present in upper - right corner of the periodic table.

Non - metals : H , He , C ,N , O , F ,P ,S , Cl, Ar , Br , Xe ,At ,Rn,  

Metalloid : They show properties of both the metals and the non - metals.

Also called as semimetals

Metalloid : B ,Si ,Ge ,As ,Sb ,Te ,Po

<u>In table F </u>:

B = metalloid  , N = non metal ( wrong-match) , Ra  = metal ( wrong-match) , He = Non - metal ( wrong-match)

<u>In table G : Correctly matched </u>

I =  Non - metal , Ca = metal , Rb = metal , As = metalloid

<u>In table H</u>:

Ni = metal ( wrong-match) , C = metalloid ( wrong-match) , Mg = metal , Pb = Metal

<u>In table J</u>:

Cu = metal , Sb = Metalloid( wrong-match)  , S = non metal( wrong-match) ,Ne = non metal

6 0
3 years ago
A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant? 2Al(s) + 3CuSO4(aq) →
vova2212 [387]

Answer:

Copper (II) sulfate

Explanation:

Given reaction is

2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Amount of aluminum = 1·25 g

Amount of copper (II) sulfate = 3·28 g

Atomic weight of Al = 26 g

Molecular weight of CuSO4 ≈ 159·5

Number of moles of Al = 1·25 ÷ 26 = 0·048

Number of moles of CuSO4 = 3·28 ÷ 159·5 = 0·021

From the above balanced chemical equation for every 2 moles of aluminum, 3 moles of copper (ll) sulfate will be required

So for 1 mole of Al, 1·5 moles of copper (ll) sulfate will be required

For 0·048 moles of Al, 1.5 × 0·048 moles of copper (ll) sulfate will be required

∴ Number of moles of copper (ll) sulfate required = 0·072

But we have only 0·021 moles of copper (ll) sulfate

As copper (ll) sulfate is not there in required amount, the limiting reactant will be copper (ll) sulfate

∴ The limiting reactant is copper (ll) sulfate

7 0
3 years ago
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