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vlabodo [156]
3 years ago
5

A radioactive nuclide that is used for geological dating has an atomic number of 19 and mass number 40. Which is the symbol of t

his nuclide?
A 19/21 K
B 21/19 K
C 40/19 K
D 19/40 K
Chemistry
2 answers:
Musya8 [376]3 years ago
5 0
I believe this nuclide is potassium with the symbol K. Atomic number for an element remains constant no matter how the mass changes. From the periodic table, potassium has an atomic number of 19.
Serjik [45]3 years ago
4 0

Answer:

40/19 K or C

Explanation:

edg

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For the reactions below, describe the reactor system and conditions you suggest to maximize the selectivity to make the desired
alexandr1967 [171]

Answer:

hello your question lacks the required reaction pairs below are the missing pairs

Reaction system 1 :

A + B ⇒ D  -r_{1A}  = 10exp[-8000K/T]C_{A}C_{B}

A + B ⇒ U -r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}

Reaction system 2

A + B ⇒ D  -r_{1A} = 10exp( -1000K/T)C_{A}C_{B}

B + D ⇒ U  -r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}

Answer : reaction 1 : description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

reaction 2 :

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

Explanation:

Reaction system 1 :

A + B ⇒ D  -r_{1A}  = 10exp[-8000K/T]C_{A}C_{B}

A + B ⇒ U -r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}

the selectivity of D is represented  using the relationship below

S_{DU} = \frac{-r1A}{-r2A}

hence SDu = 1/10 * \frac{exp(-800K/T)}{exp(-1000K/T)} * C_{A} ^{0.5} C_{B} ^{-0.5}

description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

Reaction system 2

A + B ⇒ D  -r_{1A} = 10exp( -1000K/T)C_{A}C_{B}

B + D ⇒ U  -r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}

selectivity of D

S_{DU} = \frac{-r1A}{-r2A}

hence Sdu = 1/10^7  *  \frac{exp(-1000K/T)}{exp(-10000K/T)} *\frac{C_{A} }{C_{D} }

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

3 0
3 years ago
Convert 15.78 g of H2O2 to mols. <br> Convert 15.3 mols Au to g
iren2701 [21]

Answer:

.46 moles H2O2

3,014 grams Au

Explanation:

H2O2:

15.78g (1 mol/34g) = .46 moles H2O2

Au:

15.3mol (197g/mol) = 3,014 grams Au

8 0
3 years ago
Electrons always fill orbitals in the same order. Each s orbital holds 2 electrons, each set of p orbitals holds 6 electrons, ea
arsen [322]
Oxygen is the answer :)

4 0
3 years ago
Read 2 more answers
What will occur when potassium reacts with sulfur?
sveticcg [70]
The electrons are transferred from potassium to sulphur, in this reaction, potassium is being oxidised and sulphur is being reduced. Two potassium atoms each lose one electron forming K+ ions. Sulphur gains two electrons forming S2-/2- ions. The resultant formula will be: K2S, bonding in this compound is ionic.
4 0
2 years ago
What happened to the FREQUENCY of the wave as the instrument got bigger?
Archy [21]

Answer:

The wavelengths at which resonance occurs are proportional to the length of the instrument, so you can play different notes by changing the length. In general the larger the instrument the longer the wavelength of the fundamental and the lower the frequency range of the instrument.

Explanation:

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3 years ago
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