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3 years ago

My insta is gageisgod7j7 HMU

Chemistry

2 answers:

Tcecarenko [31]3 years ago

7 0

Alright sounds good and also thank you so much for the free points dawg

PilotLPTM [1.2K]3 years ago

5 0

Answer:

Maybe ;) maybe not hmmm

Explanation:

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If you want to use a serial dilution to make a 1/50 dilution. The first dilution you make is a 1/5 dilution with a total volume

uranmaximum [27]

Answer:

0.2 mL stock solution, 0.8 solvent, 0.1 mL first solution and 0.9 solvent

Explanation:

The final volume for fist solution is 1 mL and concentration must will be 1/5, then 1 mL/5=0.2 mL. For complete the 1 mL add the missing solvent volume 1 mL-0.2 mL=0.8 mL. For second solution, assuming final volume is 1 mL, and concentration 1/10, then we have 1 mL /10=0.1 mL solution 1/5. Completing volume, 1 mL-0.1 mL= 0.9 mL solvent.

7 0

3 years ago

In a titration experiment 12.5 ml of 0.500 m h2so4 neutralized 50.0 ml of naoh. the concentration of the naoh solution is ____.

s344n2d4d5 [400]

0.250 mol/L

Step 1. Write the chemical equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Step 2. Calculate the moles of H2SO4

Moles of H2SO4 = 12.5 mL H2SO4 × (0.500 mmol H2SO4/1 mL H2SO4)

= 6.25 mmol H2SO4

Step 3. Calculate the moles of NaOH

Moles of NaOH = 6.25 mmol H2SO4 × (2 mmol NaOH/(1 mmol H2SO4)

= 12.5 mmol NaOH

Step 4. Calculate the concentration of the NaOH

[NaOH] = moles/litres = 12.5 mmol/50.0 mL = 0.250 mol/L

4 0

3 years ago

Would you vote to change the coin content or to keep them the same? Explain.

aivan3 [116]

I would not change anything, It would just confuse America. And besides, I don't see anything wrong with our current coin system.

7 0

3 years ago

Why is paraffin oil constantly stirred to determine the melting point of benzene acid?

Sidana [21]

Why is paraffin oil constantly stirred to determine the melting point of benzene acid?

Paraffin oil is used for determination of boiling point and melting point for the following reasons: It has a very high boiling point and so it can be used to maintain high temperatures in the boiling and melting point apparatus without loss of the substance.

#CarryOnLearning

7 0

3 years ago

Calculate the mass of iron(III) oxide that contains a million iron atoms. Be sure your answer has a unit symbol if necessary, an

KiRa [710]

Answer: The mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

Explanation:

We are given:

Number of iron atoms = A million = $1.0\times 10^6$

The chemical formula of the given compound is $Fe_2O_3$

It is formed by the combination of 2 iron atoms and 3 oxygen atoms.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

1 mole of iron (II) oxide will contain = $(2\times 6.022\times 10^{23})=1.2044\times 10^{24}$ number of iron atoms

We know that:

Molar mass of iron (II) oxide = 159.7 g/mol

Applying unitary method:

For $1.2044\times 10^{24}$ number of iron atoms, the mass of iron (II) oxide is 159.7 g

So, for $1.0\times 10^6$ number of iron atoms, the mass of iron (II) oxide will be $\frac{159.7}{1.2044\times 10^{24}}\times 1.0\times 10^6=2.6\times 10^{-17}g$

Hence, the mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

8 0

3 years ago