Question

Please help me solve this 5^2x=7^x+1

Answer 1

Answer:

$x=\frac{ln7}{2ln5-ln7}$

Step-by-step explanation:

5^2x=7^x+1 ⇔ ln5^2x = ln7^x+1 ⇔ 2xln5 = (x+1)ln7 ⇔ (2ln5-ln7)x = ln7

⇔ x = ln7/(2ln5-ln7)

Answer 2

It’s gonna translate to 25x=7x+1
so then 18x=1