Please help me solve this 5^2x=7^x+1

Mathematics

2 answers:

denis23 [38]3 years ago

7 0

Answer:

$x=\frac{ln7}{2ln5-ln7}$

Step-by-step explanation:

5^2x=7^x+1 ⇔ ln5^2x = ln7^x+1 ⇔ 2xln5 = (x+1)ln7 ⇔ (2ln5-ln7)x = ln7

⇔ x = ln7/(2ln5-ln7)

Mnenie [13.5K]3 years ago

5 0

It’s gonna translate to 25x=7x+1
so then 18x=1

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cestrela7 [59]

So tis is a ratio 16 is to 3 or 16:3
if use 64 tea bags then how many cups of sugar so
turn 16:3 into fraction
16:3=16/3 or 3/16, it doesn't matter
then you want to find 64:x or 64/x or x/64

we know that 16/3=64/x because it tis an equivalent ratio
so 16/3=64/x
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