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Olin [163]
3 years ago
6

Please help me solve this 5^2x=7^x+1

Mathematics
2 answers:
denis23 [38]3 years ago
7 0

Answer:

x=\frac{ln7}{2ln5-ln7}

Step-by-step explanation:

5^2x=7^x+1 ⇔ ln5^2x = ln7^x+1 ⇔ 2xln5 = (x+1)ln7 ⇔ (2ln5-ln7)x = ln7

⇔ x = ln7/(2ln5-ln7)

Mnenie [13.5K]3 years ago
5 0
It’s gonna translate to 25x=7x+1
so then 18x=1
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