Let 1993 = time 0 = 0.
Let 1999 = time 6 = 6
Let 2012 = time 19 = 19
So, a = 171 (million). First solve for k.
176 = 171 e^k6
176/171 = e^(k*6)
ln (176/171) = 6k
k = 1/6 ln (176/171)
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
Answer:
c = - 32
Step-by-step explanation:
The common ratio r of the sequence is
r = 
= 
= - 2
To find the next term in the sequence multiply the previous term by r
a = 4 × - 2 = - 8
b = - 8 × - 2 = 16
c = 16 × - 2 = - 32
Answer: 10 4/5
Convert the mixed numbers to improper fractions
Use the algebraic formula for addition of fractions:
a/b + c/d = (ad + bc) / bd
Reduce fractions and simplify if possible
