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3 years ago

8

Please help me im very confused

2 answers:

katrin [286]3 years ago

5 0

Answer:

6,-3

Step-by-step explanation:

stich3 [128]3 years ago

4 0

Answer:

(6,-3)

Step-by-step explanation:

I don't know how to explain it you got it right tho

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PLEASE NO LINKS I LOST SO MANY POINTS

Ann [662]

Answer:

We will split the trapezoid into right angle triangle and rectangle

Traingle with base 3cm and height 10 - 6 = 4cm

Area of traingle

= $\frac{1}{2}*base *height = \frac{1}{2} * 3 * 4 = 6cm^{2}$

Area of rectangle with sides 6cm and 3cm

= $6 * 3 = 18cm^{2}$

Therefore, area of the trapezoid

= $6+18 = 24cm^{2}$

Area of the semi circle with radius 3/2 = 1.5cm

= $\frac{1}{2}\pi r^{2} = \frac{1*\pi *1.5*1.5}{2} = 1.125\pi cm^{2}$

$Total area = 24 + 1.125\pi =27.53cm^{2}$

8 0

3 years ago

Fionas salary is $30,000, and she expects to receive a 3% raise each year; 10 years

schepotkina [342]

You would have to first times .03 times 10 then take that times 30,000 which should equal 900

3 0

3 years ago

Read 2 more answers

Help please! Thanks!!

Effectus [21]

Answer:

inverse of sin 1.6

or it can be written as sin^1 1.6

5 0

2 years ago

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago

Surface area of a cylinder

Paul [167]

703.4 cmsquare
Hope it helps

4 0

3 years ago