Answer:
Following are the code to this question:
def binarynumber(num):#defining a method binarynumber that accepts a parameter num
x=""#defining a string variable x
if (num!=0):#defining if condition to check number not equal to 0
while (num>=1):#defining a loop that check value is grater then equal to one
if (num %2==0):#defining if condition to check num is even
x=x+"0" #add string value 0 in num variable
num=num/2 #divide the value by 2
else:#defining else block
x=x+"1"#add string value 1 in num variable
num=(num-1)/2#first subtract 1 into num variable then divide the value by 2
else:
x="0"#assign string value 0 in num variable
return "".join(reversed(x))#return value
num = int (input ("Enter any number: "))#defining num variable that input the integer value
print (binarynumber(num))#using print method to call method binarynumber with passing num parameter
Output:
Enter any number: 12
1100
Explanation:
- In the above python code a method "binarynumber" is declared, in which the "num" variable passes as the parameter inside the method a string variable "x" is declared that stores all converted values.
- Inside the method and if the block is declared that checks number value is not equal to 0 if this condition is false then it will add string value and reverse its value.
- Or if the condition is true it defines a while loop that calculates the given number binary digits and returns its value.
- At the last step, the num variable is declared that inputs the integer value from the user end and calls the method by using the print method.
The answer is actually A. I took the test and selected the wrong answer, but A was the one the test said was right. Plz mark brainliest!!! Hope this helped! ;^)
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