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Mazyrski [523]
3 years ago
15

What are the next two terms in the given sequence? 1200, 1196, 598, 594, 297, * and what is was the rule to the given sequence?

Mathematics
1 answer:
antoniya [11.8K]3 years ago
8 0

next two terms - 293, 146.5

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Please help due in 15 minutes!!!!!
gizmo_the_mogwai [7]

Answer:

44ft

Step-by-step explanation:

The formula for circumference is 2 * π * radius and in this case we want to use 3.14 for π and so we do 2 x 3.14 x 7 because the radius is half of the diameter (14) and once you do that you end up getting 43.96 and once you round you get 44ft so you are correct.

4 0
3 years ago
Can someone answer not just use my points
bixtya [17]

Answer:

35

Step-by-step explanation:

Well if m<YVW = (12x-1) and x=3 then just plug in x

So,

m<YVW = (12(3)-1)

m<YVW = 36-1

m<YVW = 35

4 0
3 years ago
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JulijaS [17]
It is B) 11 + 7 = 18,
3 0
3 years ago
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Kalvin tosses a coin five days in a row and gets tails every time. Do you think there is something wrong with the coin? How can
riadik2000 [5.3K]
I don’t think there is anything wrong with the coming there is just a 50% chance that It would land on tails and there’s a 50% chance that it will land on heads ‍♀️☺️
7 0
4 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%28190%29%5E%7B3%7D%20%7B68%5E%7B2%7D%20%7D%20%20%5Ctimes%20%28%20%5Cfr
mrs_skeptik [129]

Answer:

  \dfrac{\sqrt[3]{95^2}}{17\cdot95^4}=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}

Step-by-step explanation:

The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)/(a^c) = a^(b-c)

__

  \dfrac{190^3}{68^2}\times\dfrac{34}{95^{\frac{19}{3}}}=\dfrac{(2\cdot 95)^3}{(2\cdot 34)^2}\cdot\dfrac{34}{95^6\cdot 95^{\frac{1}{3}}}=2^{3-2}95^{3-6-\frac{1}{3}}34^{1-2}\\\\=2\cdot 95^{-3\frac{1}{3}}\cdot 34^{-1}=2\cdot 95^{-4+\frac{2}{3}}\cdot 34^{-1}\\\\=\dfrac{2\sqrt[3]{95^2}}{95^4\cdot 34}=\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}\\\\=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}

6 0
3 years ago
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