3 years ago

Please help with number 9

Mathematics

1 answer:

RUDIKE [14]3 years ago

6 0

This is the answer i got 147

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The factorization of 8x3 -125 is (2x-5)(jx2 +kx+25)

lbvjy [14]

$\bf ~\hspace{10em}\textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 8x^3-125~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^3\\ 125=5\cdot 5\cdot 5\\ \qquad 5^3 \end{cases}\implies 2^3x^3-5^3\implies (2x)^3-5^3 \\[2em] [2x-5][(2x)^2+(2x)(5)+5^2]\implies (2x-5)(\stackrel{\stackrel{j}{\downarrow }}{4}x^2+\stackrel{\stackrel{k}{\downarrow }}{10}x+25)$

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Matthew has a 150 page book he has read one third of it how many pages has he read so far

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What is the effect on the area of a rectangle if the dimensions are doubled?

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Let x be the length and y be the width of a rectangle.
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Answer: When the dimension is doubled, the area is 4 times the original.
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3 years ago