$- 3y + 10 = x...(1) \\ 10x + 7y = - 38...(2) \\ from \: equations \: (1) \: and \: (2) \\ 10( - 3y + 10) + 7y = - 38 \\ - 30y + 100 + 7y = - 38 \\ - 23y = - 38 - 100 \\ - 23y = - 138 \\ y = \frac{ - 138}{ - 23} \\ \huge \red { \boxed{y = 6}} \\ substituting \: y = 6 \: in \: equation \: (1) \\ x = - 3 \times 6 + 10 = - 18 + 10 = - 8 \\ \huge \red { \boxed{x = - 8}} \\ \\ \: \: \huge \purple{ \boxed{(x, \: \: y) = ( - 8, \: \: 6)}}$

7 0

3 years ago

What is the value of n and the measure of 1?

IgorC [24]

Assuming that the figure is implying that angles 1 and 2 are the same, we have

$11n=14n-18 \iff 3n=18 \iff n=6$

So, the measure of angles 1 is

$11\cdot 6=66$

5 0

3 years ago

Please you all should help me with these questions

larisa86 [58]

B because it is b 2121

7 0

3 years ago

A student takes a true-false test that has 12 questions and guesses randomly at each answer. Let X be the number of questions an

snow_lady [41]

Step-by-step answer:

assuming the true-false test have equal probabilities (each 0.5), we can use the binomial probability to calculate the sum of probabilities of getting 10, 11 or 12 questions correctly out of 12.

p=probability of success = 0.5

N=number of questions

x = number of correct answers

then

P(x) = C(N,x)(p^x)((1-p)^(N-x))

where C(N,x) = N!/(x!(N-x)!) = number of combinations of taking x objects out of N.

P(10) = C(12,10)(0.5^10)((1-0.5)^2) = 33/2048 = 0.01611

P(11) = C(12,11)(0.5^11)((1-0.5)^1) = 3/1024 = 0.00293

P(12) = C(12,12)(0.5^12)((1-0.5)^0) = 1/4096 = 0.00024

for a total probability of 79/4096 = 0.01929

7 0

3 years ago