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oee [108]
3 years ago
15

I WILL GIVE YOU BRAINLEST

Mathematics
1 answer:
hjlf3 years ago
6 0
24% ............................................
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HELP PLEASE!! NO LINKS!! GIVING 20 POINTS AWAY!!
kap26 [50]
It adds up to 360.
35 + 50 + 105 = 190
360 - 190 = 170
5 0
2 years ago
Read 2 more answers
Please help me this is a hard problem
Levart [38]

Step-by-step explanation:

- 3y + 10 = x...(1) \\ 10x + 7y =  - 38...(2) \\ from \: equations \: (1) \: and \: (2) \\ 10( - 3y + 10) + 7y =  - 38 \\  - 30y + 100 + 7y =  - 38 \\  - 23y =  - 38 - 100 \\  - 23y =  - 138 \\ y =  \frac{ - 138}{ - 23}  \\  \huge \red { \boxed{y = 6}} \\ substituting \: y = 6 \: in \: equation \: (1) \\ x =  - 3 \times 6 + 10 =  - 18 + 10 =  - 8 \\   \huge \red { \boxed{x =  - 8}} \\  \\  \:  \:  \huge \purple{ \boxed{(x, \:  \: y) = ( - 8, \:  \: 6)}}

7 0
3 years ago
What is the value of n and the measure of 1?
IgorC [24]

Assuming that the figure is implying that angles 1 and 2 are the same, we have

11n=14n-18 \iff 3n=18 \iff n=6

So, the measure of angles 1 is

11\cdot 6=66

5 0
3 years ago
Please you all should help me with these questions​
larisa86 [58]
B because it is b 2121
7 0
3 years ago
A student takes a true-false test that has 12 questions and guesses randomly at each answer. Let X be the number of questions an
snow_lady [41]

Step-by-step answer:

assuming the true-false test have equal probabilities (each 0.5), we can use the binomial probability to calculate the sum of probabilities of getting 10, 11 or 12 questions correctly out of 12.

p=probability of success = 0.5

N=number of questions

x = number of correct answers

then

P(x) = C(N,x)(p^x)((1-p)^(N-x))

where C(N,x) = N!/(x!(N-x)!) = number of combinations of taking x objects out of N.

P(10) = C(12,10)(0.5^10)((1-0.5)^2) = 33/2048 = 0.01611

P(11) = C(12,11)(0.5^11)((1-0.5)^1)     =  3/1024 = 0.00293

P(12) = C(12,12)(0.5^12)((1-0.5)^0) =  1/4096 = 0.00024

for a total probability of 79/4096 = 0.01929

7 0
3 years ago
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