Answer:
The candle must burn at 2cm per hour in order to be 6cm tall after 4 hours. I know this because the candle has to burn 8cm in 4 hours and that amounts to 2cm per hour.
Step-by-step explanation:
Lets solve!
We have to find out how much of the candle needs to be burned!
14cm - 6cm = 8cm
The candle must burn 8cm in 4 hours!
Lets find out how much the candle burns in 1 hour.
= 2cm per hour
The candle must burn at 2cm per hour in order to be 6cm tall after 4 hours. I know this because the candle has to burn 8cm in 4 hours and that amounts to 2cm per hour.
Woohoo, We did it! <u>Would you like to mark my answer as brainliest?</u> I would love that!
Ok, entonces creo que sería -6 porque -6 x 3 = -16, no estoy seguro de si esto ayudará o te confundirá más, pero ten un buen día
Answer:
2.97142857143 = 104/35
Step-by-step explanation:
On calculators, anytime we're doing a fraction problem and we use calculators, It doesn't give us the fractions all it gives us is decimals, but i finally got the fraction for you. hope this helped
Make sure nobody copied and pasted my answer because i would be WILLING TO report their answer for copying and pasting
Answer: c. Nominal
Step-by-step explanation:
Level of measurement determines the nature of description .
The four levels of measurements scales are
1. Nominal scale
- Categorize the data on the basis of the quality such as Gender, color, etc.
2. Ordinal scale
- Order attributes according to their ranks. For example : 1 < 2 < 3 .
3. Interval scale
- Describe the feature of the difference between any two categories. For example : Fahrenheit scale to measure temperature.
4. Ratio scale
- Consist of the features of nominal, ordinal, and interval measures but in includes a "true zero" point.
For example : Age.
∴ A<u> nominal</u> variable is a qualitative variable such that there is no meaningful ordering or ranking of the categories.
Hence, the correct answer is c. Nominal .
Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
