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3 years ago

AGAIN SOMEONE PLEASE HELP ME.

Mathematics

1 answer:

meriva3 years ago

8 0

You need to use the law of cosine:

B^2 = A^2 + C^2 - 2ACcos(b)

55^2 = 90^2 + 50^2 - 2(50)(90)cos(b)

0.841666 = cos(b)

b = 32.68

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The table of values shown below represents a linear function. Which of these points could also be an ordered pair in the table,

maks197457 [2]

Answer:

(18,27) , because the rate of change of the function is $\frac{4}{3}$

Step-by-step explanation:

step 1

Find the slope of the linear equation

Looking at the table

we have the points (0,3) and (3,7)

The slope is equal to

$m=(7-3)/(3-0)=\frac{4}{3}$

step 2

Find the equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=\frac{4}{3}$

$b=3$ -----> point (0,3) is the y-intercept

substitute

$y=\frac{4}{3}x+3$

The rate of change of the linear equation is equal to $\frac{4}{3}$

Remember that

If a ordered pair is a solution of the linear equation, then the ordered pair must satisfy the linear equation

<u><em>Verify </em></u>

1) point (18,27)

substitute the value of x and the value of y in the linear equation

$27=\frac{4}{3}(18)+3$

$27=24+3$

$27=27$ -----> is true

The ordered pair is a solution of the linear equation

therefore

The point (18,27) could also be an ordered pair in the table

2) point (27,18)

substitute the value of x and the value of y in the linear equation

$18=\frac{4}{3}(27)+3$

$18=36+3$

$18 \neq 39$ -----> is not true

The ordered pair is not a solution of the linear equation

therefore

The point (27,18) could not be an ordered pair in the table

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