3 years ago

Identify whether each equation has one solution, infinitely many solutions, or no solution.

Mathematics

1 answer:

Orlov [11]3 years ago

6 0

Answer:

2(x - 5) = 2(x - 5) have infinitely

5(x + 4) = 5(x-6) has no salution

5(x + 4) = 3(x-6) has one salution

4(x - 2) = 4(x + 2) has no salution

x + 2(x - 5) = 3(x - 2) - 4 has infinitely

Step-by-step explanation:

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How many terms are in the expression a3 + 3a2b - 4b - 11b + 7 5 6 4 7

Contact [7]

Answer:

there are 5 terms!

Step-by-step explanation:

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2 years ago

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frozen [14]

I think its.......5/15=1/3

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3 years ago

Help please!! I will give crown! :D

GREYUIT [131]

Answer:

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Step-by-step explanation:

You move it 5 over, so it is 3.844x10^5

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2 years ago

Read 2 more answers

Which of the following sets contain all roots of the polynomial

Zarrin [17]

All these given roots are contained in option C.

The given equation is :

$9x^{3}+9x^{2}-4x-4=0$

$9x^{2}(x+1)-4(x+1)=0$

$(9x^{2}-4)(x+1)=0$

$9x^{2}-4=0,x+1=0$

$x^{2}=\frac{4}{9},x=-1$

$x=\frac{2}{3},x=-1$

Roots = $-1,\frac{-2}{3} ,\frac{2}{3}$

Hence these lie in between $(\frac{-3}{2} ,\frac{3}{2})$

8 0

3 years ago

Ellus

butalik [34]

9514 1404 393

Answer:

2.25

Step-by-step explanation:

Add the square of half the x-coefficient to complete the square.

(-3/2)² = 9/4 = 2.25

4 0

3 years ago