Answer:
The algorithm is as follows:
1. Input sentence
2. Input character
3. Length = len(sentence)
4. count = 0
5. For i = 0 to Length-1
5.1 If sentence[i] == character
5.1.1 count++
6. Print count
7. Stop
The program in C++ is as follows:
#include <iostream>
#include <string.h>
using namespace std;
int main(){
char str[100]; char chr;
cin.getline(str, 100);
cin>>chr;
int count = 0;
for (int i=0;i<strlen(str);i++){
if (str[i] == chr){
count++;} }
cout << count;
return 0;}
Explanation:
I will provide explanation for the c++ program. The explanation can also be extended to the algorithm
This declares the string and the character
char str[100]; char chr;
This gets input for the string variable
cin.getline(str, 100);
This gets input for the character variable
cin>>chr;
This initializes count to 0
int count = 0;
This iterates through the characters of the string
for (int i=0;i<strlen(str);i++){
If the current character equals the search character, count is incremented by 1
if (str[i] == chr){ count++;} }
This prints the count
cout << count;
Answer:
The answer is "Option d"
Explanation:
The scanner method is the full token of the process, that finds and returns. It is token, which is followed by both the inputs meeting and the guideline template. This method can block, even though the former instance of hasNext() is true while waiting for input, and wrong choices can be described as follows:
- In option a, It is incorrect because the character at the beginning can't be
considered.
- In option b, It is wrong because the characters are known as the word in which blank space not a part of the word.
- In option c, It is wrong because in this input before the call is not the method.
// making class
class Player {
// Data members
string name;
int score;
// Name setter
void setName(string str){
this.name = str;
}
// Score setter
void setScore(int num){
this.score = num;
}
// Score getter
int getScore(){
return score;
}
// Name getter
string getName(){
return name;
}
};
no they used standard 8088 Intel processors
hope this helps
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