Answer:
![\frac{1-\sqrt{7} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1-%5Csqrt%7B7%7D%20%7D%7B2%7D)
Step-by-step explanation:
given ![\frac{5-2\sqrt{7} }{3-\sqrt{7} }](https://tex.z-dn.net/?f=%5Cfrac%7B5-2%5Csqrt%7B7%7D%20%7D%7B3-%5Csqrt%7B7%7D%20%7D)
To rationalise the denominator multiply the numerator/ denominator by the conjugate of the denominator.
the conjugate of 3 -
is 3 +
, hence
× ![\frac{3+\sqrt{7} }{3+\sqrt{7} }](https://tex.z-dn.net/?f=%5Cfrac%7B3%2B%5Csqrt%7B7%7D%20%7D%7B3%2B%5Csqrt%7B7%7D%20%7D)
= (15 + 5
- 6
- 14 ) / (9 - 7)
=
← in simplified radical form
Answer:
2*10^-1
Step-by-step explanation:
U shud know y
The first thing we must do for this case is to find the conversion of rupees to US dollars.
Currently, the conversion is:
1 rupee = 0.014 $
Then, to find the amount of $ in 2000 rupees, we make the following rule of three:
1 rupee -----------------> 0.014 $
2000 rupees ----------> x
From here, we clear the value of x.
We have then:
![x = (2000) * (0.014) x = 28](https://tex.z-dn.net/?f=%20x%20%3D%20%282000%29%20%2A%20%280.014%29%20%20x%20%3D%2028%20%20)
Answer:
2,000 rupees are 28 US dollars.
Answer:
the answer is 62
Step-by-step explanation:
-109+321-150
212-150
62
B
Using pythagoras theorem
![a^{2} + {b}^{2} = {c}^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%20%3D%20%20%7Bc%7D%5E%7B2%7D%20)
![2 {a}^{2} + 2 {b}^{2} = 2 {c}^{2}](https://tex.z-dn.net/?f=2%20%7Ba%7D%5E%7B2%7D%20%20%2B%202%20%7Bb%7D%5E%7B2%7D%20%20%3D%202%20%7Bc%7D%5E%7B2%7D%20)
Therefore to find AC (which is 2c)
![2c = \sqrt{2( {a}^{2} + {b}^{2} )}](https://tex.z-dn.net/?f=2c%20%3D%20%20%5Csqrt%7B2%28%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%29%7D%20)
Hence it's B.