Answer:
f^-1(x)= ![\sqrt[7]{x} /8](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%7D%20%2F8)
Step-by-step explanation:
f(x)=8x^7
x^7=f(x)/8
x=![\sqrt[7]{x} /8](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%7D%20%2F8)
f^-1(x)= ![\sqrt[7]{x} /8](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%7D%20%2F8)
-10. One type of system of equations that results in infinite solutions is one where both sides of the equation are exactly equal. Here, setting the second equation equal to -10 becomes 2y - 4x = -10. This can be rearranged into 2y = 4x - 10. Dividing everything by 2 results in y = 2x - 5, which is exactly what the first equation is. Substituting one equation into another, we get 2x - 5 = 2x - 5, which is a true statement for all values of x.
To find when the ball reaches the ground, you would need to find the time that gives you a height value of zero.
Your answer would be 4 seconds
h = -16(4)^2 + 64(16)
h = -16(16) + 256
h = -256 + 256
h = 0
Hope this helps!
Answer:
B
Step-by-step explanation:
b - 3b + 15 - w + 4
-2b-w+19