Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Jon has y stickers and uses 20
jon=y-20
the sisters share y-20 between 2 of them
therefore each sister receives
(y-20) divided by 2 -- (y-20)/2
Here we will use the trial and error method.
- We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>
<h2>Now,</h2><h3>x=2</h3>
<h2>Again,</h2><h3>x=3</h3>
<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
Answer:
I belive the answer is 21.42% :)
31.
There's a pattern, +1, +2,+3,+4 ect.
