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Mkey [24]
3 years ago
9

The weather forecast predicts that today's high will be 70. Which temperature scale is being used? What would be the correspondi

ng temperature on the other two scales?
Physics
1 answer:
sweet [91]3 years ago
7 0

Answer:

<em>The temperature scale being used by the forecast is in the Fahrenheit scale.</em>

Explanation:

<u>Temperature Scales </u>

Nowadays, there are three temperature scales in use: Fahrenheit, Celsius, and Kelvin. Fahrenheit temperature scale is based on the number 32 for the freezing point of water and 212 for the boiling point of water and dividing that interval into 180 parts.

Celsius temperature scale is also known as centigrade, is based on 0 for the freezing point of water and 100 for the boiling point of water divided into 100 parts.

Finally, the Kelvin temperature scale is the base unit of the International System (SI) of measurement for thermodynamic temperature. It is defined as 1/ 273.16 of the so-called triple point (equilibrium among the solid, liquid, and gaseous phases) of pure water.

If the temperature predicted by the weather forecast was in celsius degrees, its equivalent in Fahrenheit degrees will be

F=9/5C+32=158^oF

Very high for our planet's normal temperatures. But it the prediction was in Fahrenheit degrees, the Celsius equivalent is

C=(F-32)*5/9=21^oC

A quiet nice temperature indeed.

The same temperature in the Kelvin scale is

K=C-273.16=-252^oK

So, the temperature scale being used by the forecast is in the Fahrenheit scale.

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Answer:

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Explanation:

Given that :

mass of the block   m =  200.0 g  = 200 × 10⁻³ kg

the horizontal spring constant   k  =  4500.0 N/m

position of the block (distance x) = 4.00 cm  = 0.04 m

To determine the speed the block will be traveling when it leaves the spring; we applying the  work done on the spring as it is stretched (or compressed) with the kinetic energy.

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kx^2 = mv^2

4500* 0.04^2 = 200*10^{-3} *v^2

7.2 =200*10^{-3}*v^{2}

v^{2}   =\frac{7.2}{200*10^{-3}}

v   =\sqrt{\frac{7.2}{200*10^{-3}}}

v = 6 m/s

Hence,the speed the block will be traveling when it leaves the spring is  6 m/s

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