Answer:
It travels 1414 feets.
Explanation:
Let's take the length the bullet travels <em>l </em>as the hypotenuse of a right triangle and the height it reaches one of its sides. Since we got the angle α at which it was fired and the height <em>h</em> it reached, we can calculate <em>l</em> using the <em>sin(α)</em> function:
![sin(\alpha )=\frac{opposite side}{hypotenuse}\\sin(\alpha)=\frac{h}{l}\\l=\frac{h}{sin(\alpha)}](https://tex.z-dn.net/?f=sin%28%5Calpha%20%29%3D%5Cfrac%7Bopposite%20side%7D%7Bhypotenuse%7D%5C%5Csin%28%5Calpha%29%3D%5Cfrac%7Bh%7D%7Bl%7D%5C%5Cl%3D%5Cfrac%7Bh%7D%7Bsin%28%5Calpha%29%7D)
Replacing:
![l=\frac{1000ft}{sin(\frac{\pi}{4})}](https://tex.z-dn.net/?f=l%3D%5Cfrac%7B1000ft%7D%7Bsin%28%5Cfrac%7B%5Cpi%7D%7B4%7D%29%7D)
Solving and roundin to the nearest foot:
![l=1414 ft](https://tex.z-dn.net/?f=l%3D1414%20ft)
Answer:
![W_x = 0.9156\ c](https://tex.z-dn.net/?f=W_x%20%3D%200.9156%5C%20c)
Explanation:
given,
velocity of particle 1 = 0.741 c to left
velocity of second particle = 0.543 c to right
relative velocity between the particle = ?
for the relative velocity calculation we have formula
![W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}](https://tex.z-dn.net/?f=W_x%20%3D%20%5Cdfrac%7B%7Cu_x%20-%20v_x%7C%7D%7B1-%5Cdfrac%7Bu_xv_x%7D%7Bc%5E2%7D%7D)
u_x = 0.543 c
v_x = - 0.741 c
![W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}](https://tex.z-dn.net/?f=W_x%20%3D%20%5Cdfrac%7B0.543%20c%20-%20%28-0.741%20c%29%7D%7B1-%5Cdfrac%7B%280.543%20c%29%28-0.741%20c%29%7D%7Bc%5E2%7D%7D)
![W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}](https://tex.z-dn.net/?f=W_x%20%3D%20%5Cdfrac%7B0.543%20c%20%2B0.741%20c%29%7D%7B1%2B%5Cdfrac%7B%280.543%29%280.741%29c%5E2%7D%7Bc%5E2%7D%7D)
![W_x = \dfrac{1.284c}{1+0.402363}](https://tex.z-dn.net/?f=W_x%20%3D%20%5Cdfrac%7B1.284c%7D%7B1%2B0.402363%7D)
![W_x = 0.9156\ c](https://tex.z-dn.net/?f=W_x%20%3D%200.9156%5C%20c)
Relative velocity of the particle is ![W_x = 0.9156\ c](https://tex.z-dn.net/?f=W_x%20%3D%200.9156%5C%20c)
Answer:
Rate of heat is 45.1 kJ/min
Explanation:
Heat required to evaporate the water is given by
Q = mL
here we know that
![L = 2.25 \times 10^6 J/kg](https://tex.z-dn.net/?f=L%20%3D%202.25%20%5Ctimes%2010%5E6%20J%2Fkg)
now we have
![Q = (0.200)(2.25 \times 10^6 J/kg)](https://tex.z-dn.net/?f=Q%20%3D%20%280.200%29%282.25%20%5Ctimes%2010%5E6%20J%2Fkg%29)
![Q = 452.1 kJ](https://tex.z-dn.net/?f=Q%20%3D%20452.1%20kJ)
now the power is defined as rate of energy
![P = \frac{Q}{t}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BQ%7D%7Bt%7D)
![P = \frac{452.1 kJ}{10}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B452.1%20kJ%7D%7B10%7D)
![P = 45.1 kJ/min](https://tex.z-dn.net/?f=P%20%3D%2045.1%20kJ%2Fmin)
The correct option is (b) 5n
As a result, there is a net downward force of 5N operating on the object.
The resultant force is the force that results from adding the vector sums of all the forces operating on an item. The combined action of all the acting forces on the object produces the same effect as the resulting force. When determining the resulting force, the direction of the forces must be taken into account.
Given;
The northward force is Fn = 10N
The southward force is Fs = 15N
Required;
The net force on the mobile phone is Fnet = ?N
The object's weight exerts downward pressure, and upward resistance exerts upward pressure. The vector sum of these two forces will be the net force.
Fnet = Fs - Fn (Considering the direction downward as positive)
Fnet= 15N - 10N
Fnet = 5N
As a result, there is a net downward force of 5 N operating on the object.
Learn more about the Force with the help of the given link:
brainly.com/question/7362815
#SPJ4
Answer:
primary source
Explanation:
the explanation is in the image above
brainliest please