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pogonyaev
3 years ago
5

Object A experiences an attractive force of 50 N when it comes close to Object B. If Object A is positively charged, what can yo

u say about Object B?
1. You cannot tell from the information given.
2. Object B is negatively charged.
3. Object B is positively charged.
4. Object B is neutral.
Physics
2 answers:
dexar [7]3 years ago
8 0
B object b is negatively charged
denis23 [38]3 years ago
4 0
It is B since they are traveling at the same speed one is positive so the other had to be negative hope this helps;)))))
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Based on observations, the speed of a jogger can be approximated by the relation v 5 7.5(1 2 0.04x) 0.3, where v and x are expre
castortr0y [4]

Answer:

solution:

to find the speed of a jogger use the following relation:  

V

=

d

x

/d

t

=

7.5

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i

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r

...........................(

1

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in Above equation in x and t. Separating the variables and integrating,

∫

d

x

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×=

∫

d

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or

−

4.7619  

=

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Here C =constant of integration.   

x

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0  at  t

=

0

, we get:  C

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4.7619

now we have the relation to find the position and time for the jogger as:

−

4.7619  =

t

−

4.7619

.

.

.

.

.

.

.

.

.

(

2

)

Here

x  is measured in miles and  t  in hours.

(a) To find the distance the jogger has run in 1 hr, we set t=1 in equation (2),    

     to get:

      = −

4.7619  

      =  

1

−

4.7619

      = −

3.7619

  or  x

=

7.15

m

i

l

e

s

(b) To find the jogger's acceleration in   m

i

l

/

differentiate  

     equation (1) with respect to time.

     we have to eliminate x from the equation (1) using equation (2).  

     Eliminating x we get:

     v

=

7.5×

     Now differentiating above equation w.r.t time we get:

      a

=

d

v/

d

t

       =

−

0.675

/

      At  

      t

=

0

      the joggers acceleration is :

       a

=

−

0.675

m

i

l

/

        =

−

4.34

×

f

t

/  

(c)  required time for the jogger to run 6 miles is obtained by setting  

        x

=

6  in equation (2).  We get:

        −

4.7619

(

1

−

(

0.04

×

6  )

)^

7

/

10=

t

−

4.7619

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s

6 0
3 years ago
In most materials, as heat energy is absorbed, density
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Answer:

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5 0
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Answer:

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