You are looking for sin, which is the opposite side over the hypotenuse. You can use "<u>S</u>ome <u>o</u>ther<u> h</u>ippy<u> c</u>aught <u>a</u>nother <u>h</u>ippy <u>t</u>ripping <u>o</u>n <u>a</u>cid" to remember <u>S</u>in=<u>o</u>pposite/<u>h</u>ypotenuse; <u>C</u>os= <u>a</u>djacent/<u> h</u>ypotenuse; <u>T</u>an= <u>o</u>pposite/<u>a</u>djacent.