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2 years ago

20 points! I need help with these!

Mathematics

1 answer:

defon2 years ago

5 0

1. 113.64

(work) 947x.12

2. 130.5

(work) 435x.30 = 130.5

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Abby used the quadratic formula to find the zeros of the

MArishka [77]

Step 2: She did not simplify under the square root correctly

under the square root:

(-6)^2 =36

and -4(5)(-8) =160

therefore under the square root it needs to be square root of 36+160 which is square root of 196.

That answer is 14 when square rooted

5 0

2 years ago

Read 2 more answers

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

6 0

3 years ago

tickets for the school play cost $ 8 each for adults and $ 3 for students.what was the cost of 2 adult tickets and 1 student tic

olga nikolaevna [1]

the answer is $19,because you add the cost of 2 adult tickets 18$ and the cost of 1 student ticket 3$ and get 19$

5 0

3 years ago

the fourth term of an arithmetic sequence is 141, and the seventh term is 132. what is the first term?

Cerrena [4.2K]

The 1st, 4th, and 7th terms make an arithmetic sequence of their own. The 4th term is the average of the 1st and 7th, so ...
(1st +7th)/2 = 4th
1st + 7th = 2×4th
1st = 2×4th - 7th

The first term is ...
2*141 - 132 = 150

7 0

2 years ago

Can i please get some (help on my maths)

quester [9]

$ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}$

$We\ have:\\\\15x^2+7x-12=0\\\\a=15;\ b=7;\ c=-12\\\\substitute\\\\x_1=\dfrac{-7-\sqrt{7^2-4\cdot15\cdot(-12)}}{2\cdot15}=\dfrac{-7-\sqrt{49-5(15)(-12)}}{30}\\\\x_2=\dfrac{-7+\sqrt{49-4(15)(-12)}}{30}$

First option.

5 0

3 years ago