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Svetllana [295]
3 years ago
8

B) How many terms are thereS.a) Find the value of x:3 155 2x35​

Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

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Step-by-step explanation:

???

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What is the distance from the origin to point A graphed on the complex plane below?
Lisa [10]

Answer:

a. square root of 5

b. square root of 13

c. 9

d. 13

Step-by-step explanation:

6 0
3 years ago
Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
2 years ago
A credit card has an annual percentage rate of 23 988% the balanced owed is $1450.00. Assuming no additional charges are made. W
tatyana61 [14]
The answer should be 120.83
8 0
2 years ago
Identify the 33rd term of the arithmetic sequence 9, 7 and one half, 6...
marta [7]

Answer:

  -39

Step-by-step explanation:

The general term of an arithmetic sequence is ...

  an = a1 +d(n -1)

This sequence has first term a1=9 and common difference d=(7.5-9) = -1.5. Then the 33rd term is ...

  a33 = 9 -1.5(33 -1) = 9 -48 = -39

The 33rd term is -39.

5 0
3 years ago
A van travels at a constant speed of x km/hr over a distance of 45km/hr. If the van increases its speed by 4km/h, it will be abl
harkovskaia [24]
Speed = Distance/Time. Let speed be V, distance D and time T

a)Given: D₁ =45km, V₁=x km/h 
V₁=D₁/T
V₁=45/T OR T= 45/V₁

b) Given : D₂ =48 km and V₂ = V₁ + 4 km/h
V₂ = 48/T, but V₂ = V₁+4, then:

V₁+4 = 48/T OR  T=48/(V₁+4). Since Time is same, then we can write:
45/V₁ =48/(V₁+4), solve for V₁:
45V₁ + 180 = 48V₁

3V₁ =180 and V₁ = x = 60 km/h
8 0
2 years ago
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