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Sergio039 [100]
4 years ago
8

Two angles are right angles, if and only if they are congruent. Is that true?

Mathematics
1 answer:
Fofino [41]4 years ago
5 0
If those two angles are congruent and supplementary, then they are a right angle. Hope that helped!
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AthXL for School:
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$28.5

Step-by-step explanation:

14-6.5=7.5

7.5x$3.8=28.5

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Which function is represented by the graph?<br><br> |–x + 3|<br> –|x + 3|<br> –|x| + 3<br> |–x| + 3
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C i had this question a while ago
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Read 2 more answers
The lengths of three sides of a quadrilateral are shown below:
lubasha [3.4K]

Answer:

  (A) 8y^2 +8y -10

  (B) 22y^3 +2y^2 +2y -7

  (C) yes, for these polynomials. The result of adding or subtracting the polynomials in this problem is another polynomial, suggesting the set of polynomials is closed to addition and subtraction.

Step-by-step explanation:

A. (4y + 2y^2 − 3) + (−4 + 2y^2 + 2y) + (4y^2 − 3 + 2y)

  = y^2(2 +2 +4) +y(4 +2 +2) +(-3 -4 -3)

  = 8y^2 +8y -10 . . . . total length of sides 1, 2, 3

__

B. The length of the 4th side is the difference between the perimeter and the sum of the other three sides:

  (22y^3 + 10y^2 + 10y − 17) -(8y^2 +8y -10)

  = 22y^3 +y^2(10 -8) +y(10 -8) +(-17 +10)

  = 22y^3 +2y^2 +2y -7 . . . . length of 4th side

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C. The result of adding or subtracting the polynomials in this problem is another polynomial, suggesting the set of polynomials is closed to addition and subtraction. An example is not a proof, but there is nothing about this example that would suggest a different conclusion.

6 0
4 years ago
On Monday Harold picked up six donuts and two large coffees for the office staff. He paid $5.80. On Tuesday, Melinda picked up f
Lina20 [59]

Cost of tjhe donut: D

Cost of the large coffee: C

On Monday Harold picked up six donuts and two large coffees for the office staff, he paid $5.80:

6D+2C=5.80

On Tuesday, Melinda picked up four donuts and 5 large coffees for the office staff. She paid $7.02:

4D+5C=7.02

Use the next system of linear equations to find the value of D and C:

\begin{gathered} 6D+2C=5.80 \\ 4D+5C=7.02 \end{gathered}

1. Solve D in the first equation:

\begin{gathered} \text{Subtract 2C in both sides of the equation:} \\ 6D+2C-2C=5.80-2C \\ 6D=5.80-2C \\  \\ \text{Divide both sides of the equation into 6:} \\ \frac{6}{6}D=\frac{5.80}{6}-\frac{2}{6}C \\  \\ D=\frac{5.80}{6}-\frac{1}{3}C \end{gathered}

2. Substitute the D in the second equation by the equation you get in step 1:

4(\frac{5.80}{6}-\frac{1}{3}C)+5C=7.02

3. Solve C:

\begin{gathered} \frac{23.2}{6}-\frac{4}{3}C+5C=7.02 \\  \\ \frac{-4C+15C}{3}=7.02-\frac{23.2}{6} \\  \\ \frac{11}{3}C=\frac{42.12-23.2}{6} \\  \\ \frac{11}{3}C=\frac{18.92}{6} \\  \\ C=\frac{3}{11}\cdot\frac{18.92}{6} \\  \\ C=\frac{56.76}{66} \\  \\ C=0.86 \end{gathered}

4. Use the value of C=0.86 to find D;

\begin{gathered} D=\frac{5.80}{6}-\frac{1}{3}C \\  \\ D=\frac{5.80}{6}-\frac{1}{3}(0.86) \\  \\ D=\frac{5.80}{6}-\frac{0.86}{3} \\  \\ D=\frac{17.4-5.16}{18} \\  \\ D=\frac{12.24}{18} \\  \\ D=0.68 \end{gathered}

The solution fot the system is:

\begin{gathered} C=0.86 \\ D=0.68 \end{gathered}<h2>The cost of one dount is $0.68</h2><h2>The cost of one large coffee is $0.86</h2>

4 0
1 year ago
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