All categories

3 years ago

Find the derivative of y with respect to the appropriate variable y=cos^-1(x^2)

Mathematics

1 answer:

Ksju [112]3 years ago

3 0

Answer:

a. Practically speaking, you compute the differential in much the same way you compute a derivative via implicit differentiation, but you omit the variable with respect to which you are differentiating.

Aside: Compare this to what happens when you differentiate both sides with respect to some other independent parameter, say :

b. This is just a matter of plugging

Step-by-step explanation:

like if this was helpful

You might be interested in

I need a 30 x axes and 30 y axes graph single quadrant graph please. BRAINLYIST REWARDED

kvv77 [185]

Yes, because the ratios are equivalent between each pair of values.

6 0

2 years ago

Read 2 more answers

For f(x) = 3x +1 and g(x) = x2 – 6, find (f- g)(x).

Fiesta28 [93]

Answer:

$\boxed{\sf (f-g)(x) = -{x}^{2} + 3x + 7}$

Given:

$\sf f(x) = 3x + 1 \\ \sf g(x) = {x}^{2} - 6$

To find:

$\sf (f - g)(x) = f(x) - g(x)$

Step-by-step explanation:

$\sf \implies(f - g)x = f(x) - g(x) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3x + 1) - ( {x}^{2} - 6) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3x + 1) + (- {x}^{2} + 6) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3x + 1 - {x}^{2} + 6 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - {x}^{2} + 3x + 1 + 6 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = -{x}^{2} + 3x + 7$

8 0

3 years ago

The graph of h(x) is shown. Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which

fgiga [73]

Answer:

x-intercept

The point at which the curve crosses the x-axis, so when y = 0.

From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)

y-intercept

The point at which the curve crosses the y-axis, so when x = 0.

From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)

Asymptote

A line which the curve gets infinitely close to, but never touches.

From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5

(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).

5 0

2 years ago

Read 2 more answers

HELP!!!

just olya [345]

Answer:

I am not sure but I think a or d is answer

I'm not quiet sure

4 0

3 years ago

Express 15.16 as a mixed number

kap26 [50]

If this is not a typo, and you mean 15.16 as in 15 and 16 hundredths, we can express this into a mixed number.
Mixed numbers are a whole number with the remainder of that number as a fraction.
For example, 1.25 as a decimal = 1 1/4 as a mixed number.
Since we already have our whole number, 15, we need to know what 16 hundredths is simplified as a fraction.
Currently, our mixed number is 15 16/100.
To simplify this, we need to find a common factor that 16 and 100 share.
Since they are both even numbers, let's divide by 2.
16/2 = 8
100/2 = 50.
Our new mixed number is 15 8/50.
Currently our fraction is still even, so divide by 2 again.
8/2 = 4
50/2 = 25
Your new mixed number is 15 4/25.
4 and 25 have no common factors, so the fraction is simplified.
Your answer is:
15.16 is 15 4/25 as a mixed number.
I hope this helps!

4 0

3 years ago

Read 2 more answers