The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
Answer:
The first and third answer I believe.
Step-by-step explanation:
The side with 3 can go over 1.5, since they are both at the same side. It will be equivalent to 4 over 2 because they are also the same side. (1st option)
Multiplying each side by 1/2, does result you to the final image.
3 multiplied by 1/2 is 1.5
4 multiplied by 2 is 2
Respuesta:
(2945.411; 3054.589)
Explicación paso a paso:
Dado ;
Tamaño de la muestra, n = 50
Media, xbar = 3000
Desviación estándar, s = 200
Nivel de confianza, Zcrítico al 95% = 1,96
El intervalo de confianza se define como:
Xbar ± margen de error
Margen de error = Zcrítico * s / sqrt (n)
Margen de error = 1,96 * 200 / sqrt (50)
Margen de error = 54.589
Límite inferior = (3000 - 54.589) = 2945.411
Límite superior = (3000 + 54.589) = 3054.589
(2945.411; 3054.589)
